Trying to build a PC (counter) for the nand2tetris book, but I'm having some trouble with the logic

StackOverflow https://stackoverflow.com/questions/15034037

  •  11-03-2022
  •  | 
  •  

Вопрос

Here's my code:

CHIP PC {
    IN in[16],load,inc,reset;
    OUT out[16];

    PARTS:
    Inc16(in = regout, out = incout);
    Mux16(a = regout, b = incout, sel = inc, out = incdecision);
    Mux16(a = incdecision, b = false, sel = reset, out = resetdecision);
    Mux16(a = regout, b = resetdecision, sel = load, out = loaddecision);
    Register(in = loaddecision, load = true, out = regout, out = out);
}

Basically, the value coming out of the register is incremented, which is only accepted if inc is 1 (checked via Mux) which then goes through another Mux which may reset it, and then another Mux which may or may not write it depending on the value of load. Then whatever value came out of that (be it the changed value or the value coming from the old register) is put into the register.

What am I doing wrong?

Это было полезно?

Решение

You don't seem to have the In signal connected to anything. If the load signal is set you need to get the appropriate Mux16 to load the In value into the register.

Другие советы

Change the order of resetdecision and loaddecesion. First one has higher priority.

Inc16(in=outpc, out=outincreased);
Mux16(a=outpc, b=outincreased, sel=inc, out=outinc);
Mux16(a=outinc, b=in, sel=load, out=outload);
Mux16(a=outload, b=false, sel=reset, out=outreset); 
    //And16(a=outLOAD, b[0..15]=reset, out=outreset);
Register(in=outreset, load=true, out=out, out=outpc);

The reset Mux16 needs to happen after the load Mux16. The load Mux16 needs to have "in" as the "b" pin.

My working code from Nand2Tetris:

Inc16(in = outandabout, out = incout);
Mux16( a = outandabout, b = incout, sel = inc, out = incinc);
Mux16( a = incinc, b = in, sel = load, out = loadout);
Mux16( a = loadout, b = false, sel = reset, out= outreset);
Register(in = outreset, load = true, out = out, out = outandabout);
Лицензировано под: CC-BY-SA с атрибуция
Не связан с StackOverflow
scroll top