Is it possible for a python function to ignore unused kwargs [duplicate]

Question

This question already has answers here:

How does one ignore unexpected keyword arguments passed to a function? (6 answers)

Closed 2 years ago.

If I have a simple function:

def add(a, b, c):
    return a + b + c

Is it possible for me to make it so that if I supply an unused kwarg, it is simply ignored?

kwargs = dict(a=1, b=2, c=3, d=4)
print add(**kwargs) #prints 6

Answer 1

Sure. Just add **kwargs to the function signature:

def add(a, b, c, **kwargs):
    return a + b + c

kwargs = dict(a=1, b=2, c=3, d=4)
print add(**kwargs) 
#prints 6