Вопрос

Given several .xls files with varying number of sheets, I am reading them into R usingread.xls from the gdata package. I have two related issues (solving the second issue should solve the first):

  1. It is unknown ahead of time how many sheets each .xls file will have, and in fact this value will vary from one file to the next.
  2. I need to capture the name of the sheet, which is relevant data

Right now, to resolve (1), I am using try() and iterating over sheet numbers until I hit an error.

How can I grab a list of the names of the sheet so that I can iterate over them?

Это было полезно?

Решение

See the sheetCount and sheetNames functions (on same help page) in gdata. If xls <- "a.xls", say, then reading all sheets of a spreadsheet into a list, one sheet per component, is just this:

sapply(sheetNames(xls), read.xls, xls = xls, simplify = FALSE)

Note that the components will be named using the names of the sheets. Depending on the content it might make sense to remove simplify = FALSE.

Другие советы

For such tasks I use library XLConnect. With its functions you can get the names of each sheet in a vector and then just determine the length of that vector.

#Read your workbook 
wb<-loadWorkbook("Your_workbook.xls")

#Save each sheet's name as a vector
lp<-getSheets(wb)

#Now read each sheet as separate list element
dat<-lapply(seq_along(lp),function(i) readWorksheet(wb,sheet=lp[i]))

UPDATE

As suggested by @Martin Studer XLConnect functions are already vectorized, so there is no need to use lapply(), instead just provide vector of sheet names or use function getSheets() inside readWorksheet().

dat <- readWorksheet(wb, sheet = getSheets(wb))
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