Вопрос

The following code prints 4 as expected:

let x=21
let x=$x-1
echo $x

But the following prints 16:

let x=000021
let x=$x-1
echo $x

Could someone explain the difference?

Это было полезно?

Решение

00021 is an octal constant. The output 16 is the correct decimal result. To get the octal value use

printf "%o\n" $x

Remove the leading zeros if the number is decimal.

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