Keep it in a variable and use it whenever you like.
$location = Get-FileName
copy $location c:\temp
start $location
Вопрос
I've been trying to figure this out for a while, but no luck, I would like to pop up a file open dialog, which I have been able to do with a function I found online, and then use the file location further down the line in my script, but I can't figure it out.
Here is the function
Function Get-FileName()
{
[System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms") |
Out-Null
$OpenFileDialog = New-Object System.Windows.Forms.OpenFileDialog
$OpenFileDialog.initialDirectory = "C:\Users\$($env:username)\Documents\"
$OpenFileDialog.filter = "CSV's (*.csv)| *.csv"
$OpenFileDialog.ShowDialog() | Out-Null
$OpenFileDialog.filename
}
I'm new to powershell so I'm not sure how functions work.
Решение
Keep it in a variable and use it whenever you like.
$location = Get-FileName
copy $location c:\temp
start $location