سؤال

I have added labels to the Zoomable Icicle Layout example provided here: http://bl.ocks.org/mbostock/1005873

I rotate the labels based on available space using the following:

.attr("transform", function (d) {
     return (x(d.x + d.dx) - x(d.x)) > 50 ?
          ("translate(" + (x(d.x + d.dx / 2)) + "," + (y(d.y + d.dy / 2)) + ")rotate(0)") :
          ("translate(" + (x(d.x + d.dx / 2)) + "," + (y(d.y + d.dy / 2)) + ")rotate(90)"); })

which rotates the label 90' if the space is too small to keep it horizontal.

What I would like to know is how to get the rotation value of each d?

هل كانت مفيدة؟

المحلول

You can abstract out the code which determines the rotation angle simplify the expression as:

function rotation(d, x) {
    return (x(d.x + d.dx) - x(d.x)) > 50 ? 0 : 90;
}

// ...
.attr("transform", function (d) {  
      return "translate(" + [(x(d.x + d.dx / 2)), (y(d.y + d.dy / 2))] + ")" +  
             "rotate(" + rotation(d, x) + ")";
})

Then whenever you need the value of rotation of a point which is bound to data d, call rotation(d, x).

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