Domanda

I have added labels to the Zoomable Icicle Layout example provided here: http://bl.ocks.org/mbostock/1005873

I rotate the labels based on available space using the following:

.attr("transform", function (d) {
     return (x(d.x + d.dx) - x(d.x)) > 50 ?
          ("translate(" + (x(d.x + d.dx / 2)) + "," + (y(d.y + d.dy / 2)) + ")rotate(0)") :
          ("translate(" + (x(d.x + d.dx / 2)) + "," + (y(d.y + d.dy / 2)) + ")rotate(90)"); })

which rotates the label 90' if the space is too small to keep it horizontal.

What I would like to know is how to get the rotation value of each d?

È stato utile?

Soluzione

You can abstract out the code which determines the rotation angle simplify the expression as:

function rotation(d, x) {
    return (x(d.x + d.dx) - x(d.x)) > 50 ? 0 : 90;
}

// ...
.attr("transform", function (d) {  
      return "translate(" + [(x(d.x + d.dx / 2)), (y(d.y + d.dy / 2))] + ")" +  
             "rotate(" + rotation(d, x) + ")";
})

Then whenever you need the value of rotation of a point which is bound to data d, call rotation(d, x).

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