由于纬度和经度,和距离,我想找到一个边界框
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22-07-2019 - |
题
给定纬度和经度,和距离,我想找到的边界框,其中的距离小于给定的距离。
这个问题在这里问:的如何计算边界框对于给定的纬度/经度位置?
我想DONOT此partcularly准确,所以我已经修改和它简化为
def boundingBox(latitudeInDegrees, longitudeInDegrees, halfSideInKm):
lat = math.radians(latitudeInDegrees)
lon = math.radians(longitudeInDegrees)
halfSide = 1000*halfSideInKm
RADIUS_OF_EARTH = 6371
# Radius of the parallel at given latitude
pradius = radius*math.cos(lat)
latMin = lat - halfSide/radius
latMax = lat + halfSide/radius
lonMin = lon - halfSide/pradius
lonMax = lon + halfSide/pradius
rad2deg = math.degrees
return (rad2deg(latMin), rad2deg(lonMin), rad2deg(latMax), rad2deg(lonMax))
但我不能明白这是怎么工作的,尤其是这行没有意义的,我halfSide = 1000*halfSideInKm
解决方案
这线从公里转换边界框单位为米。
其他提示
此代码也不太工作,它跳到KM和M之间。
固定代码,由名的详细PEP8风格,并增加了一个简单的框对象:
class BoundingBox(object):
def __init__(self, *args, **kwargs):
self.lat_min = None
self.lon_min = None
self.lat_max = None
self.lon_max = None
def get_bounding_box(latitude_in_degrees, longitude_in_degrees, half_side_in_miles):
assert half_side_in_miles > 0
assert latitude_in_degrees >= -90.0 and latitude_in_degrees <= 90.0
assert longitude_in_degrees >= -180.0 and longitude_in_degrees <= 180.0
half_side_in_km = half_side_in_miles * 1.609344
lat = math.radians(latitude_in_degrees)
lon = math.radians(longitude_in_degrees)
radius = 6371
# Radius of the parallel at given latitude
parallel_radius = radius*math.cos(lat)
lat_min = lat - half_side_in_km/radius
lat_max = lat + half_side_in_km/radius
lon_min = lon - half_side_in_km/parallel_radius
lon_max = lon + half_side_in_km/parallel_radius
rad2deg = math.degrees
box = BoundingBox()
box.lat_min = rad2deg(lat_min)
box.lon_min = rad2deg(lon_min)
box.lat_max = rad2deg(lat_max)
box.lon_max = rad2deg(lon_max)
return (box)
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