如何动态合并两个 JavaScript 对象的属性?
-
05-07-2019 - |
题
我需要能够在运行时合并两个(非常简单的)JavaScript 对象。例如我想:
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
有谁有这方面的脚本或知道内置的方法来做到这一点?我不需要递归,也不需要合并函数,只需要平面对象上的方法。
解决方案
ECMAScript 2018标准方法
您可以使用对象传播:
let merged = {...obj1, ...obj2};
/** There's no limit to the number of objects you can merge.
* Later properties overwrite earlier properties with the same name. */
const allRules = {...obj1, ...obj2, ...obj3};
ECMAScript 2015(ES6)标准方法
/* For the case in question, you would do: */
Object.assign(obj1, obj2);
/** There's no limit to the number of objects you can merge.
* All objects get merged into the first object.
* Only the object in the first argument is mutated and returned.
* Later properties overwrite earlier properties with the same name. */
const allRules = Object.assign({}, obj1, obj2, obj3, etc);
(参见 MDN JavaScript Reference )
ES5和早期的方法
for (var attrname in obj2) { obj1[attrname] = obj2[attrname]; }
请注意,这只会将 obj2
的所有属性添加到 obj1
,如果您仍想使用未修改的 obj1
,这可能不是您想要的代码>
如果你正在使用一个框架来破坏你的原型,那么你必须得到像 hasOwnProperty
这样的检查,但是这个代码适用于99%的情况。
示例功能:
/**
* Overwrites obj1's values with obj2's and adds obj2's if non existent in obj1
* @param obj1
* @param obj2
* @returns obj3 a new object based on obj1 and obj2
*/
function merge_options(obj1,obj2){
var obj3 = {};
for (var attrname in obj1) { obj3[attrname] = obj1[attrname]; }
for (var attrname in obj2) { obj3[attrname] = obj2[attrname]; }
return obj3;
}
其他提示
jQuery还有一个实用工具: http://api.jquery.com/jQuery.extend / 。
取自jQuery文档:
// Merge options object into settings object
var settings = { validate: false, limit: 5, name: "foo" };
var options = { validate: true, name: "bar" };
jQuery.extend(settings, options);
// Now the content of settings object is the following:
// { validate: true, limit: 5, name: "bar" }
上述代码将改变名为 settings
的现有对象。
如果您想在不修改任何参数的情况下创建新对象,请使用以下命令:
var defaults = { validate: false, limit: 5, name: "foo" };
var options = { validate: true, name: "bar" };
/* Merge defaults and options, without modifying defaults */
var settings = $.extend({}, defaults, options);
// The content of settings variable is now the following:
// {validate: true, limit: 5, name: "bar"}
// The 'defaults' and 'options' variables remained the same.
Harmony ECMAScript 2015(ES6)指定 Object.assign
将执行此操作。
Object.assign(obj1, obj2);
我用google搜索代码来合并对象属性,最后来到这里。但是由于没有任何递归合并代码,我自己写了。 (也许jQuery扩展是递归BTW?)无论如何,希望其他人也会觉得它很有用。
(现在代码不使用 Object.prototype
:)
代码
/*
* Recursively merge properties of two objects
*/
function MergeRecursive(obj1, obj2) {
for (var p in obj2) {
try {
// Property in destination object set; update its value.
if ( obj2[p].constructor==Object ) {
obj1[p] = MergeRecursive(obj1[p], obj2[p]);
} else {
obj1[p] = obj2[p];
}
} catch(e) {
// Property in destination object not set; create it and set its value.
obj1[p] = obj2[p];
}
}
return obj1;
}
一个例子
o1 = { a : 1,
b : 2,
c : {
ca : 1,
cb : 2,
cc : {
cca : 100,
ccb : 200 } } };
o2 = { a : 10,
c : {
ca : 10,
cb : 20,
cc : {
cca : 101,
ccb : 202 } } };
o3 = MergeRecursive(o1, o2);
生成对象o3,如
o3 = { a : 10,
b : 2,
c : {
ca : 10,
cb : 20,
cc : {
cca : 101,
ccb : 202 } } };
请注意, underscore.js
的 extend
-method 在单行中执行此操作:
_.extend({name : 'moe'}, {age : 50});
=> {name : 'moe', age : 50}
与jQuery extend()类似,您在 AngularJS 中具有相同的功能:
// Merge the 'options' object into the 'settings' object
var settings = {validate: false, limit: 5, name: "foo"};
var options = {validate: true, name: "bar"};
angular.extend(settings, options);
我今天需要合并对象,这个问题(和答案)对我帮助很大。我尝试了一些答案,但没有一个符合我的需求,所以我结合了一些答案,自己添加了一些东西,并提出了一个新的合并功能。这是:
var merge = function() {
var obj = {},
i = 0,
il = arguments.length,
key;
for (; i < il; i++) {
for (key in arguments[i]) {
if (arguments[i].hasOwnProperty(key)) {
obj[key] = arguments[i][key];
}
}
}
return obj;
};
一些示例用法:
var t1 = {
key1: 1,
key2: "test",
key3: [5, 2, 76, 21]
};
var t2 = {
key1: {
ik1: "hello",
ik2: "world",
ik3: 3
}
};
var t3 = {
key2: 3,
key3: {
t1: 1,
t2: 2,
t3: {
a1: 1,
a2: 3,
a4: [21, 3, 42, "asd"]
}
}
};
console.log(merge(t1, t2));
console.log(merge(t1, t3));
console.log(merge(t2, t3));
console.log(merge(t1, t2, t3));
console.log(merge({}, t1, { key1: 1 }));
您可以使用对象传播属性&#8212;目前是第3阶段ECMAScript提案
const obj1 = { food: 'pizza', car: 'ford' };
const obj2 = { animal: 'dog' };
const obj3 = { ...obj1, ...obj2 };
console.log(obj3);
在分配之前,应修改给定的解决方案以检查 for..in
循环中的 source.hasOwnProperty(property)
- 否则,最终会复制属性整个原型链,很少需要...
在一行代码
中合并N个对象的属性 Object.assign
方法是ECMAScript 2015(ES6)标准的一部分,可以完全满足您的需求。 (不支持 IE
)
var clone = Object.assign({}, obj);
Object.assign()方法用于将所有可枚举的自有属性的值从一个或多个源对象复制到目标对象。
支持旧浏览器的 polyfill :
if (!Object.assign) {
Object.defineProperty(Object, 'assign', {
enumerable: false,
configurable: true,
writable: true,
value: function(target) {
'use strict';
if (target === undefined || target === null) {
throw new TypeError('Cannot convert first argument to object');
}
var to = Object(target);
for (var i = 1; i < arguments.length; i++) {
var nextSource = arguments[i];
if (nextSource === undefined || nextSource === null) {
continue;
}
nextSource = Object(nextSource);
var keysArray = Object.keys(nextSource);
for (var nextIndex = 0, len = keysArray.length; nextIndex < len; nextIndex++) {
var nextKey = keysArray[nextIndex];
var desc = Object.getOwnPropertyDescriptor(nextSource, nextKey);
if (desc !== undefined && desc.enumerable) {
to[nextKey] = nextSource[nextKey];
}
}
}
return to;
}
});
}
以下两个可能是一个很好的起点。 lodash还有针对这些特殊需求的定制功能!
_.extended
( http://underscorejs.org/#extend )
_。合并
( https://lodash.com/docs#merge )
顺便说一下,你们所做的就是覆盖属性,而不是合并......
这就是JavaScript对象区域真正合并的方式:只有到
对象中不是对象本身的键才会被中的覆盖。其他所有内容都将 真正合并 。当然,您可以将此行为更改为不覆盖任何存在的内容,例如仅当
到[n]未定义
等时......:
var realMerge = function (to, from) {
for (n in from) {
if (typeof to[n] != 'object') {
to[n] = from[n];
} else if (typeof from[n] == 'object') {
to[n] = realMerge(to[n], from[n]);
}
}
return to;
};
用法:
var merged = realMerge(obj1, obj2);
这是我的刺痛
- 支持深度合并
- 不会改变参数
- 采用任意数量的参数
- 不扩展对象原型
- 不依赖于其他库( jQuery , MooTools ,下划线.js 等。)
- 包括检查hasOwnProperty
-
简短:)
/* Recursively merge properties and return new object obj1 <- obj2 [ <- ... ] */ function merge () { var dst = {} ,src ,p ,args = [].splice.call(arguments, 0) ; while (args.length > 0) { src = args.splice(0, 1)[0]; if (toString.call(src) == '[object Object]') { for (p in src) { if (src.hasOwnProperty(p)) { if (toString.call(src[p]) == '[object Object]') { dst[p] = merge(dst[p] || {}, src[p]); } else { dst[p] = src[p]; } } } } } return dst; }
醇>
示例:
a = {
"p1": "p1a",
"p2": [
"a",
"b",
"c"
],
"p3": true,
"p5": null,
"p6": {
"p61": "p61a",
"p62": "p62a",
"p63": [
"aa",
"bb",
"cc"
],
"p64": {
"p641": "p641a"
}
}
};
b = {
"p1": "p1b",
"p2": [
"d",
"e",
"f"
],
"p3": false,
"p4": true,
"p6": {
"p61": "p61b",
"p64": {
"p642": "p642b"
}
}
};
c = {
"p1": "p1c",
"p3": null,
"p6": {
"p62": "p62c",
"p64": {
"p643": "p641c"
}
}
};
d = merge(a, b, c);
/*
d = {
"p1": "p1c",
"p2": [
"d",
"e",
"f"
],
"p3": null,
"p5": null,
"p6": {
"p61": "p61b",
"p62": "p62c",
"p63": [
"aa",
"bb",
"cc"
],
"p64": {
"p641": "p641a",
"p642": "p642b",
"p643": "p641c"
}
},
"p4": true
};
*/
<强> Object.assign()强>
ECMAScript 2015(ES6)
这是一项新技术,是ECMAScript 2015(ES6)标准的一部分。 该技术的规范已经完成,但请查看兼容性表,了解各种浏览器的使用情况和实施状态。
Object.assign()方法用于将所有可枚举的自有属性的值从一个或多个源对象复制到目标对象。它将返回目标对象。
var o1 = { a: 1 };
var o2 = { b: 2 };
var o3 = { c: 3 };
var obj = Object.assign(o1, o2, o3);
console.log(obj); // { a: 1, b: 2, c: 3 }
console.log(o1); // { a: 1, b: 2, c: 3 }, target object itself is changed.
对于不太复杂的对象,您可以使用 JSON :
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog', car: 'chevy'}
var objMerge;
objMerge = JSON.stringify(obj1) + JSON.stringify(obj2);
// {"food": "pizza","car":"ford"}{"animal":"dog","car":"chevy"}
objMerge = objMerge.replace(/\}\{/, ","); // \_ replace with comma for valid JSON
objMerge = JSON.parse(objMerge); // { food: 'pizza', animal: 'dog', car: 'chevy'}
// Of same keys in both objects, the last object's value is retained_/
请注意,在此示例中,“} {&quot; 一定不能在字符串中出现 !
执行此操作的最佳方法是使用Object.defineProperty添加不可枚举的适当属性。
通过这种方式,您仍然可以迭代对象属性,而无需新创建的“扩展”按钮。如果你用Object.prototype.extend创建属性,你会得到。
希望这会有所帮助:
Object.defineProperty(Object.prototype, "extend", { enumerable: false, value: function(from) { var props = Object.getOwnPropertyNames(from); var dest = this; props.forEach(function(name) { if (name in dest) { var destination = Object.getOwnPropertyDescriptor(from, name); Object.defineProperty(dest, name, destination); } }); return this; } });
一旦你开始工作,你就可以:
var obj = { name: 'stack', finish: 'overflow' } var replacement = { name: 'stock' }; obj.extend(replacement);
我刚刚在这里写了一篇关于它的博客文章: http:// onemoredigit.com/post/1527191998/extending-objects-in-node-js
您只需使用jQuery extend
var obj1 = { val1: false, limit: 5, name: "foo" };
var obj2 = { val2: true, name: "bar" };
jQuery.extend(obj1, obj2);
现在 obj1
包含 obj1
和 obj2
Prototype 有:
Object.extend = function(destination,source) {
for (var property in source)
destination[property] = source[property];
return destination;
}
obj1.extend(obj2)
会做你想要的。
如果有人使用 Google Closure Library :
goog.require('goog.object');
var a = {'a': 1, 'b': 2};
var b = {'b': 3, 'c': 4};
goog.object.extend(a, b);
// Now object a == {'a': 1, 'b': 3, 'c': 4};
var a = [1, 2];
var b = [3, 4];
goog.array.extend(a, b); // Extends array 'a'
goog.array.concat(a, b); // Returns concatenation of array 'a' and 'b'
我扩展了 David Coallier 的方法:
- 添加了合并多个对象的可能性
- 支持深度物体
- 覆盖参数(如果最后一个参数是布尔值则检测到)
如果 override 为 false,则不会覆盖任何属性,但会添加新属性。
用法:obj.merge(合并...[,覆盖]);
这是我的代码:
Object.defineProperty(Object.prototype, "merge", {
enumerable: false,
value: function () {
var override = true,
dest = this,
len = arguments.length,
props, merge, i, from;
if (typeof(arguments[arguments.length - 1]) === "boolean") {
override = arguments[arguments.length - 1];
len = arguments.length - 1;
}
for (i = 0; i < len; i++) {
from = arguments[i];
if (from != null) {
Object.getOwnPropertyNames(from).forEach(function (name) {
var descriptor;
// nesting
if ((typeof(dest[name]) === "object" || typeof(dest[name]) === "undefined")
&& typeof(from[name]) === "object") {
// ensure proper types (Array rsp Object)
if (typeof(dest[name]) === "undefined") {
dest[name] = Array.isArray(from[name]) ? [] : {};
}
if (override) {
if (!Array.isArray(dest[name]) && Array.isArray(from[name])) {
dest[name] = [];
}
else if (Array.isArray(dest[name]) && !Array.isArray(from[name])) {
dest[name] = {};
}
}
dest[name].merge(from[name], override);
}
// flat properties
else if ((name in dest && override) || !(name in dest)) {
descriptor = Object.getOwnPropertyDescriptor(from, name);
if (descriptor.configurable) {
Object.defineProperty(dest, name, descriptor);
}
}
});
}
}
return this;
}
});
示例和测试用例:
function clone (obj) {
return JSON.parse(JSON.stringify(obj));
}
var obj = {
name : "trick",
value : "value"
};
var mergeObj = {
name : "truck",
value2 : "value2"
};
var mergeObj2 = {
name : "track",
value : "mergeObj2",
value2 : "value2-mergeObj2",
value3 : "value3"
};
assertTrue("Standard", clone(obj).merge(mergeObj).equals({
name : "truck",
value : "value",
value2 : "value2"
}));
assertTrue("Standard no Override", clone(obj).merge(mergeObj, false).equals({
name : "trick",
value : "value",
value2 : "value2"
}));
assertTrue("Multiple", clone(obj).merge(mergeObj, mergeObj2).equals({
name : "track",
value : "mergeObj2",
value2 : "value2-mergeObj2",
value3 : "value3"
}));
assertTrue("Multiple no Override", clone(obj).merge(mergeObj, mergeObj2, false).equals({
name : "trick",
value : "value",
value2 : "value2",
value3 : "value3"
}));
var deep = {
first : {
name : "trick",
val : "value"
},
second : {
foo : "bar"
}
};
var deepMerge = {
first : {
name : "track",
anotherVal : "wohoo"
},
second : {
foo : "baz",
bar : "bam"
},
v : "on first layer"
};
assertTrue("Deep merges", clone(deep).merge(deepMerge).equals({
first : {
name : "track",
val : "value",
anotherVal : "wohoo"
},
second : {
foo : "baz",
bar : "bam"
},
v : "on first layer"
}));
assertTrue("Deep merges no override", clone(deep).merge(deepMerge, false).equals({
first : {
name : "trick",
val : "value",
anotherVal : "wohoo"
},
second : {
foo : "bar",
bar : "bam"
},
v : "on first layer"
}));
var obj1 = {a: 1, b: "hello"};
obj1.merge({c: 3});
assertTrue(obj1.equals({a: 1, b: "hello", c: 3}));
obj1.merge({a: 2, b: "mom", d: "new property"}, false);
assertTrue(obj1.equals({a: 1, b: "hello", c: 3, d: "new property"}));
var obj2 = {};
obj2.merge({a: 1}, {b: 2}, {a: 3});
assertTrue(obj2.equals({a: 3, b: 2}));
var a = [];
var b = [1, [2, 3], 4];
a.merge(b);
assertEquals(1, a[0]);
assertEquals([2, 3], a[1]);
assertEquals(4, a[2]);
var o1 = {};
var o2 = {a: 1, b: {c: 2}};
var o3 = {d: 3};
o1.merge(o2, o3);
assertTrue(o1.equals({a: 1, b: {c: 2}, d: 3}));
o1.b.c = 99;
assertTrue(o2.equals({a: 1, b: {c: 2}}));
// checking types with arrays and objects
var bo;
a = [];
bo = [1, {0:2, 1:3}, 4];
b = [1, [2, 3], 4];
a.merge(b);
assertTrue("Array stays Array?", Array.isArray(a[1]));
a = [];
a.merge(bo);
assertTrue("Object stays Object?", !Array.isArray(a[1]));
a = [];
a.merge(b);
a.merge(bo);
assertTrue("Object overrides Array", !Array.isArray(a[1]));
a = [];
a.merge(b);
a.merge(bo, false);
assertTrue("Object does not override Array", Array.isArray(a[1]));
a = [];
a.merge(bo);
a.merge(b);
assertTrue("Array overrides Object", Array.isArray(a[1]));
a = [];
a.merge(bo);
a.merge(b, false);
assertTrue("Array does not override Object", !Array.isArray(a[1]));
我的 equals 方法可以在这里找到: JavaScript 中的对象比较
在 MooTools 中,有一个 Object.merge():
Object.merge(obj1, obj2);
合并对象很简单。
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog', car: 'BMW' }
var obj3 = {a: "A"}
var mergedObj = Object.assign(obj1,obj2,obj3)
console.log(mergedObj);
对象从右向左合并,这意味着将覆盖与其右侧对象具有相同属性的对象。
在此示例中 obj2.car
覆盖 obj1.car
在 Ext&nbsp; JS 4中,可按以下方式完成:
var mergedObject = Ext.Object.merge(object1, object2)
// Or shorter:
var mergedObject2 = Ext.merge(object1, object2)
参见 合并(对象):对象 。
基于 Markus'和 vsync'回答,这是一个扩展版本。该函数接受任意数量的参数。它可用于在 DOM 节点上设置属性,并制作值的深层副本。但是,第一个参数是通过引用给出的。
要检测DOM节点,请使用isDOMNode()函数(请参阅Stack&nbsp;溢出问题 JavaScript isDOM&#8212 ;如何检查JavaScript对象是否是DOM对象? )
在 Opera 11,Firefox 6中进行了测试, Internet&nbsp; Explorer&nbsp; 8 和Google Chrome 16。
代码
function mergeRecursive() {
// _mergeRecursive does the actual job with two arguments.
var _mergeRecursive = function (dst, src) {
if (isDOMNode(src) || typeof src !== 'object' || src === null) {
return dst;
}
for (var p in src) {
if (!src.hasOwnProperty(p))
continue;
if (src[p] === undefined)
continue;
if ( typeof src[p] !== 'object' || src[p] === null) {
dst[p] = src[p];
} else if (typeof dst[p]!=='object' || dst[p] === null) {
dst[p] = _mergeRecursive(src[p].constructor===Array ? [] : {}, src[p]);
} else {
_mergeRecursive(dst[p], src[p]);
}
}
return dst;
}
// Loop through arguments and merge them into the first argument.
var out = arguments[0];
if (typeof out !== 'object' || out === null)
return out;
for (var i = 1, il = arguments.length; i < il; i++) {
_mergeRecursive(out, arguments[i]);
}
return out;
}
一些例子
设置HTML元素的innerHTML和样式
mergeRecursive(
document.getElementById('mydiv'),
{style: {border: '5px solid green', color: 'red'}},
{innerHTML: 'Hello world!'});
合并数组和对象。请注意,undefined可用于保留左侧数组/对象中的值。
o = mergeRecursive({a:'a'}, [1,2,3], [undefined, null, [30,31]], {a:undefined, b:'b'});
// o = {0:1, 1:null, 2:[30,31], a:'a', b:'b'}
任何不属于JavaScript对象(包括null)的参数都将被忽略。除第一个参数外,DOM节点也被丢弃。请注意,即像新String()一样创建的字符串实际上是对象。
o = mergeRecursive({a:'a'}, 1, true, null, undefined, [1,2,3], 'bc', new String('de'));
// o = {0:'d', 1:'e', 2:3, a:'a'}
如果要将两个对象合并为一个新对象(不影响两者中的任何一个),请将{}作为第一个参数
var a={}, b={b:'abc'}, c={c:'cde'}, o;
o = mergeRecursive(a, b, c);
// o===a is true, o===b is false, o===c is false
修改(由ReaperSoon提供):
还要合并数组
function mergeRecursive(obj1, obj2) {
if (Array.isArray(obj2)) { return obj1.concat(obj2); }
for (var p in obj2) {
try {
// Property in destination object set; update its value.
if ( obj2[p].constructor==Object ) {
obj1[p] = mergeRecursive(obj1[p], obj2[p]);
} else if (Array.isArray(obj2[p])) {
obj1[p] = obj1[p].concat(obj2[p]);
} else {
obj1[p] = obj2[p];
}
} catch(e) {
// Property in destination object not set; create it and set its value.
obj1[p] = obj2[p];
}
}
return obj1;
}
哇..这是我见过多个页面的第一篇StackOverflow帖子。抱歉添加另一个“答案”
此方法适用于 ES5&amp;早些时候 - 还有很多其他解决ES6问题的答案。
我没有看到任何使用”深层“对象合并Global_Objects / Function / arguments“rel =”noreferrer“> arguments
属性。这是我的答案 - 紧凑&amp; 递归,允许传递无限制的对象参数:
function extend() {
for (var o = {}, i = 0; i < arguments.length; i++) {
// if (arguments[i].constructor !== Object) continue;
for (var k in arguments[i]) {
if (arguments[i].hasOwnProperty(k)) {
o[k] = arguments[i][k].constructor === Object ? extend(o[k] || {}, arguments[i][k]) : arguments[i][k];
}
}
}
return o;
}
注释掉的部分是可选的..它只会跳过不是对象传递的参数(防止错误)。
示例:强>
extend({
api: 1,
params: {
query: 'hello'
}
}, {
params: {
query: 'there'
}
});
// outputs {api: 1, params: {query: 'there'}}
这个答案现在只是海洋中的一滴......
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
// result
result: {food: "pizza", car: "ford", animal: "dog"}
使用jQuery.extend() - 链接
// Merge obj1 & obj2 to result
var result1 = $.extend( {}, obj1, obj2 );
使用_.merge() - 链接
// Merge obj1 & obj2 to result
var result2 = _.merge( {}, obj1, obj2 );
使用_.extend() - 链接
// Merge obj1 & obj2 to result
var result3 = _.extend( {}, obj1, obj2 );
使用Object.assign()ECMAScript 2015(ES6) - 链接
// Merge obj1 & obj2 to result
var result4 = Object.assign( {}, obj1, obj2 );
所有
的输出obj1: { animal: 'dog' }
obj2: { food: 'pizza', car: 'ford' }
result1: {food: "pizza", car: "ford", animal: "dog"}
result2: {food: "pizza", car: "ford", animal: "dog"}
result3: {food: "pizza", car: "ford", animal: "dog"}
result4: {food: "pizza", car: "ford", animal: "dog"}
你应该使用lodash的 defaultsDeep
_.defaultsDeep({ 'user': { 'name': 'barney' } }, { 'user': { 'name': 'fred', 'age': 36 } });
// → { 'user': { 'name': 'barney', 'age': 36 } }
使用 Underscore.js ,合并一个对象数组:
var arrayOfObjects = [ {a:1}, {b:2, c:3}, {d:4} ];
_(arrayOfObjects).reduce(function(memo, o) { return _(memo).extend(o); });
结果是:
Object {a: 1, b: 2, c: 3, d: 4}
值得一提的是, 140byt.es集合中的版本正在最小空间内解决任务,并且为此目的值得一试:
代码:
function m(a,b,c){for(c in b)b.hasOwnProperty(c)&&((typeof a[c])[0]=='o'?m(a[c],b[c]):a[c]=b[c])}
用于您的目的:
m(obj1,obj2);
这是原创要点。