using $output to display field from MySQL
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30-06-2022 - |
Frage
In my RSVP page I want to be able to bring up a message to guests showing the name along with a message saying "You have been invited to ......".
I have added a field in my database rsvpEvent and double checked the naming is correct.
If someone could look at this page http://amy-and-duncan-are-getting-married.co.uk/rsvp/.
First name : craig
Last name : test
Password : rsvp
Here is the line of code I have added
if($attendee != null) {
// hey we found something, we should move on and print out any associated users and let them rsvp
$output = "<div>\r\n";
if(strtolower($attendee->rsvpStatus) == "noresponse") {
$output .= RSVP_START_PARA."Hi ".htmlspecialchars(stripslashes($attendee->firstName." ".$attendee->lastName)).RSVP_END_PARA;
$output .= RSVP_START_PARA."You have been invited to ".($attendee->rsvpEvent).RSVP_END_PARA;
/*if(trim(get_option(OPTION_WELCOME_TEXT)) != "") {
$output .= RSVP_START_PARA.trim(get_option(OPTION_WELCOME_TEXT)).RSVP_END_PARA;
} else {
$output .= RSVP_START_PARA.__("There are a few more questions we need to ask you if you could please fill them out below to finish up the RSVP process.", 'rsvp-plugin').RSVP_END_PARA;
}*/
$output .= rsvp_frontend_main_form($attendee->id);
} else {
$output .= rsvp_frontend_prompt_to_edit($attendee);
}
return rsvp_handle_output($text, $output."</div>\r\n");
}
Line 7 is the new line of code that has been added, can someone tell me where I am going wrong?
Keine korrekte Lösung
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