Frage

I have two columns in one of my tables called TIME_OUT and TIME_IN. These are both decimal values. I basically want to sum the difference of these columns. I have the query below that outputs the difference with no issue, but I'd like to then SUM the difference:

SELECT (TIME_IN-TIME_OUT) AS DIFF FROM TABLE_timelogs WHERE YEAR(LOG_DATE) = YEAR(NOW());

+------+
| DIFF | 
+------+
| 10.0 |
|  4.0 |
|  3.0 |
+------+

Is there a way to integrate SUM into the query so that the ultimate output is 17.0? Thank you in advance!

War es hilfreich?

Lösung

Add SUM to your query so the query reads:

SELECT SUM(TIME_IN-TIME_OUT) AS DIFF 
FROM TABLE_timelogs 
WHERE YEAR(LOG_DATE) = YEAR(NOW());

This adds the contents of the column 'diff'.

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