Add SUM to your query so the query reads:
SELECT SUM(TIME_IN-TIME_OUT) AS DIFF
FROM TABLE_timelogs
WHERE YEAR(LOG_DATE) = YEAR(NOW());
This adds the contents of the column 'diff'.
Question
I have two columns in one of my tables called TIME_OUT and TIME_IN. These are both decimal values. I basically want to sum the difference of these columns. I have the query below that outputs the difference with no issue, but I'd like to then SUM the difference:
SELECT (TIME_IN-TIME_OUT) AS DIFF FROM TABLE_timelogs WHERE YEAR(LOG_DATE) = YEAR(NOW());
+------+
| DIFF |
+------+
| 10.0 |
| 4.0 |
| 3.0 |
+------+
Is there a way to integrate SUM into the query so that the ultimate output is 17.0? Thank you in advance!
La solution
Add SUM to your query so the query reads:
SELECT SUM(TIME_IN-TIME_OUT) AS DIFF
FROM TABLE_timelogs
WHERE YEAR(LOG_DATE) = YEAR(NOW());
This adds the contents of the column 'diff'.