How to convert a GEOS MultiLineString to Polygon using Python?
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23-10-2019 - |
Question
I am developing a GeoDjango application where users can upload map files and do some basic mapping operations like querying features inside polygons.
I recognized that users happen to upload "MultiLineString"s instead of "Polygon"s sometimes. This causes the queries expecting closed geometries to fail.
What is the best way to convert a MultiLineString object to a Polygon in Python?
Thanks.
-- oMat
Solution
Hehe, at first I wrote this:
def close_geometry(self, geometry):
if geometry.empty or geometry[0].empty:
return geometry # empty
if(geometry[-1][-1] == geometry[0][0]):
return geometry # already closed
result = None
for linestring in geom:
if result is None:
resultstring = linestring.clone()
else:
resultstring.extend(linestring.coords)
geom = Polygon(resultstring)
return geom
but then I discovered that there is a nifty little method called convex_hull that does the polygon conversion for you automatically.
>>> s1 = LineString((0, 0), (1, 1), (1, 2), (0, 1))
>>> s1.convex_hull
<Polygon object at ...>
>>> s1.convex_hull.coords
(((0.0, 0.0), (0.0, 1.0), (1.0, 2.0), (1.0, 1.0), (0.0, 0.0)),)
>>> m1=MultiLineString(s1)
>>> m1.convex_hull
<Polygon object at...>
>>> m1.convex_hull.coords
(((0.0, 0.0), (0.0, 1.0), (1.0, 2.0), (1.0, 1.0), (0.0, 0.0)),)
OTHER TIPS
This small code can save a lot of time, maybe later a shorter form in geopandas will be incorporated.
import geopandas as gpd
from shapely.geometry import Polygon, mapping
def linestring_to_polygon(fili_shps):
gdf = gpd.read_file(fili_shps) #LINESTRING
geom = [x for x in gdf.geometry]
all_coords = mapping(geom[0])['coordinates']
lats = [x[1] for x in all_coords]
lons = [x[0] for x in all_coords]
polyg = Polygon(zip(lons, lats))
return gpd.GeoDataFrame(index=[0], crs=gdf.crs, geometry=[polyg])
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