AWK print record posterior to matched record (the post that already exists is about fields, not records)

Question

I have this issue written on the title, I'm trying this:

awk '{tamal = match($0,/Pattern/)}{ if (tamal == NULL) ;else print $0;} {if (tamal == NULL) ;else NR=$NR+1;print $0 }' File

Well, for some of you, it obviously doesn't work, I have been trying using different ways to modify the NR, but I've been doing it wrong.

What I want is like this:

Taco de pollo 
213451346257 
Taco de carne 
4358363693 
Ensalada 
432523498 
El mejor Taco 
234238485

and obtain this if the pattern is:

Taco

:

Taco de pollo 
213451346257 
Taco de carne 
4358363693 
El mejor Taco 
234238485

Answer 1

The pattern match prints the previous line, then the matched line. Then prev variable is assigned to the current line - when the following line is parsed prev holds the previous line.

awk  '/Taco/ {print prev;print $0} {prev=$0}' datafile

Answer 2

This grep should do:

grep -B 1 Taco datafile

-B 1 Before one line.