The pattern match prints the previous line, then the matched line. Then prev
variable is assigned to the current line - when the following line is parsed prev
holds the previous line.
awk '/Taco/ {print prev;print $0} {prev=$0}' datafile
문제
I have this issue written on the title, I'm trying this:
awk '{tamal = match($0,/Pattern/)}{ if (tamal == NULL) ;else print $0;} {if (tamal == NULL) ;else NR=$NR+1;print $0 }' File
Well, for some of you, it obviously doesn't work, I have been trying using different ways to modify the NR, but I've been doing it wrong.
What I want is like this:
Taco de pollo
213451346257
Taco de carne
4358363693
Ensalada
432523498
El mejor Taco
234238485
and obtain this if the pattern is:
Taco
:
Taco de pollo
213451346257
Taco de carne
4358363693
El mejor Taco
234238485
해결책
The pattern match prints the previous line, then the matched line. Then prev
variable is assigned to the current line - when the following line is parsed prev
holds the previous line.
awk '/Taco/ {print prev;print $0} {prev=$0}' datafile
다른 팁
This grep
should do:
grep -B 1 Taco datafile
-B 1
Before one line.