Question

I realize this is a contrived example, but I want a compile check to prevent this...

class A {};
class B : public A {};
class C : public A {};

class D : public B, public C
{
    BOOST_STATIC_ASSERT((is_base_of_once<A,D>::value))
};
Was it helpful?

Solution

The following should work:

BOOST_STATIC_ASSERT(((A*)(D*)0 == 0)) 

If A exists twice, this should rise an ambiguity error, while otherwise the test will always succeed (because it compares two null pointers).

OTHER TIPS

When I try to derive a class twice as you have here it does not even compile. (duplicate base type)

If you really want to, you an test both your base classes:

class A {};
class B : public A {};
class C : public A {};

class D : public B, public C
{
    static_assert(!(is_base_of<A,B>::value && is_base_of<A,C>::value),
                   "Invalid inheritance!");
};

Otherwise you can make the classes inherit virtually from A, so that there will still only be one instance of it in the derived class:

class A {};
class B : public virtual A {};
class C : public virtual A {};

class D : public B, public C
{
    // only one A here
};
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