different type of instantiating on c++

Question

since I've came from c# to c++ everything looks crazy for me in c++. I just wondering If someone could explain me why do we have these kind of instantiating in c++ : method 1:

ClassA obj1; // this is going to stack

method 2:

ClassA *obj1 = new ClassA(); //this is going to heap

whereas we don't have the common instantiating in C# way on c++ :

ClassA  obj2 = new obj2();

and one more question in method1 I get an instance from the ClassA but without the () and this is the exact place the I've got confused , why do we have to instatiating like that? our ClassA has an constructor but instantiating without parentheses??? how come we call its constructor?

p.s : I've read these topics :

Different methods for instantiating an object in C++

Stack, Static, and Heap in C++

What and where are the stack and heap?

Answer 1

Indeed moving to C++ from a language like Java or C# can be daunting, I've gone through it as well.

The first and foremost difference is that in C++ you almost always manage your own memory. When creating an object on the heap you are responsible for deleting it so it does not leak memory - this in turn means you can delete it when you see fit. When creating an object on the stack, it is automatically deleted when it goes out of scope - you must be careful not to use it after it goes out of scope.

Example:

void do_queue(B& queue)
{
    Evt *e = new Evt;
    queue.queueEvent(e); 
} // all well, e can be popped and used (also must be deleted by someone else!)

versus

void do_queue(B& queue)
{
    Evt e;
    queue.queueEvent(&e); 
} // e is out of scope here, popping it from the queue and using it will most likely cause a sigseg

That being said, the two methods are also significantly different in one aspect: the first one creates an object. The second one creates a pointer to an object. The nice thing about having pointers is that you can pass them around as parameters with only minimal memory being copied on the stack (the pointer is copied, instead of the whole object). Of course, you can always get the address of an object allocated on the stack by using "&", or pass it around as a reference - however, when using objects allocated on the stack you much be especially careful with their scope.

I've found this website a great resource when I moved from Java to C++: http://www.parashift.com/c++-faq-lite/ - you will probably find it too, it offers a lot of good explanations

Answer 2

In C++, you have to decide where you want your object to reside. By where I mean in which memory, the stack, or the heap.

Instantiating an object is a two steps process. First you need memory, and either you take it on the stack, or you allocate it from the heap. Second, you initializes the memory with the values you want, i.e. you construct the object, by calling its constructor function.

These two syntax are for these two possible different memory locations: the stack, and the heap.

Regarding the syntax and the apparently missing parenthesis for the stack allocated object, it is to disambiguate between the definition and construction of an object, and the declaration of a function. Indeed, ClassA obj(); declares a function taking no parameter, and returning a ClassA object.

Answer 3

C++ syntax is just like that. If you want to use the default constructor, you just call it like that:

ClassA obj1;

If you would have a constructor with a parameter, you would call it like this:

ClassA obj1(5);