Question

insertion_procedure (int a[], int p [], int N)
{
    int i,j,k;
    for (i=0; i<=N; i++) p[i] = i;
    for (i=2; i<=N; i++)
    {
        k = p[i];
        j = 1;
        while (a[p[j-1]] > a[k]) {p[j] = p[j-1]; j--}
        p[j] = k;
    }
}

I have to find cyclomatic complexity for this code and then suggest some white box test cases and black box test cases. But I am having trouble making a CFG for the code.

Would appreciate some help on test cases as well.

Was it helpful?

Solution

Start by numbering the statements:

 insertion_procedure (int a[], int p [], int N)
 {
(1)    Int i,j,k;
(2)    for ((2a)i=0; (2b)i<=N; (2c)i++) 
(3)        p[i] = i;
(4)    for ((4a)i=2; (4b)i<=N; (4c)i++)
       {
(5)       k=p[i];j=1;
(6)       while (a[p[j-1]] > a[k]) {
(7)           p[j] = p[j-1]; 
(8)           j--
          }
(9)          p[j] = k;
       }

Now you can clearly see which statement executes first and which last etc. so drawing the cfg becomes simple.

CFG

Now, to calculate cyclomatic complexity you use one of three methods:

  1. Count the number of regions on the graph: 4
  2. No. of predicates (red on graph) + 1 : 3 + 1 = 4
  3. No of edges - no. of nodes + 2: 14 - 12 + 2 = 4.

OTHER TIPS

The cyclomatic complexity is 4.

1 for the procedure +1 for the for loop +1 for the while loop +1 for the if condition of the while loop.

You can also use McCabe formula M = E-N + 2C
E = edges
N = nodes
C = components
M = cyclomatic complexity

E = 14
N = 12
C = 1

M = 14-12 + 2*1 = 4

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