& 0xFF
is redundant and makes no difference in the given case
Converting int to a byte array
Pregunta
Most bitshift solutions I have seen for converting an int to a byte array go like this:
return new byte [] {
(byte) ((i >> 24) & 0xFF),
(byte) ((i >> 16) & 0xFF),
(byte) ((i >> 8) & 0xFF),
(byte) (i & 0xFF);
}
Why the & 0xFF??
Solución
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