Question

Most bitshift solutions I have seen for converting an int to a byte array go like this:

return new byte [] {
    (byte) ((i >> 24) & 0xFF),
    (byte) ((i >> 16) & 0xFF),
    (byte) ((i >> 8) & 0xFF),
    (byte) (i & 0xFF);
}

Why the & 0xFF??

Était-ce utile?

La solution

& 0xFF is redundant and makes no difference in the given case

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