Question

$originalDate1 = '2013-12-30';

echo $newDate = date("o-m-d", strtotime($originalDate1));

Displaying 2014 instead of 2013

Était-ce utile?

La solution

The problem is the "o"

ISO-8601 year number. This has the same value as Y, except that if the ISO week number (W) belongs to the previous or next year, that year is used instead. (added in PHP 5.1.0)

You should use "Y" instead.

Autres conseils

use Y-m-d instead of o-m-d

$originalDate1 = '2013-12-30';

echo $newDate = date("Y-m-d", strtotime($originalDate1)); // will output 2014-12-30
Licencié sous: CC-BY-SA avec attribution
Non affilié à StackOverflow
scroll top