Вопрос

$originalDate1 = '2013-12-30';

echo $newDate = date("o-m-d", strtotime($originalDate1));

Displaying 2014 instead of 2013

Это было полезно?

Решение

The problem is the "o"

ISO-8601 year number. This has the same value as Y, except that if the ISO week number (W) belongs to the previous or next year, that year is used instead. (added in PHP 5.1.0)

You should use "Y" instead.

Другие советы

use Y-m-d instead of o-m-d

$originalDate1 = '2013-12-30';

echo $newDate = date("Y-m-d", strtotime($originalDate1)); // will output 2014-12-30
Лицензировано под: CC-BY-SA с атрибуция
Не связан с StackOverflow
scroll top