champs concaténer à l'aide de connexion par avant
-
28-10-2019 - |
Question
Avoir la my_tabe
tableau suivant:
M01 | 1
M01 | 2
M02 | 1
Je veux requête dessus afin d'obtenir:
M01 | 1,2
M02 | 1
J'ai réussi à se rapprocher en utilisant la requête suivante:
with my_tabe as
(
select 'M01' as scycle, '1' as sdate from dual union
select 'M01' as scycle, '2' as sdate from dual union
select 'M02' as scycle, '1' as sdate from dual
)
SELECT scycle, ltrim(sys_connect_by_path(sdate, ','), ',')
FROM
(
select scycle, sdate, rownum rn
from my_tabe
order by 1 desc
)
START WITH rn = 1
CONNECT BY PRIOR rn = rn - 1
Cédant:
SCYCLE | RES
M02 | 1,2,1
M01 | 1,2
Ce qui est faux. Il est semble que je suis proche, mais je crains que je ne pas ce à l'étape suivante ...
Des conseils?
La solution
Vous devez restreindre votre connect by
à la même valeur scycle
, et compte également le nombre de correspondances et filtre que pour éviter de voir les résultats intermédiaires.
with my_tabe as
(
select 'M01' as scycle, '1' as sdate from dual union
select 'M01' as scycle, '2' as sdate from dual union
select 'M02' as scycle, '1' as sdate from dual
)
select scycle, ltrim(sys_connect_by_path(sdate, ','), ',')
from
(
select distinct sdate,
scycle,
count(1) over (partition by scycle) as cnt,
row_number() over (partition by scycle order by sdate) as rn
from my_tabe
)
where rn = cnt
start with rn = 1
connect by prior rn + 1 = rn
and prior scycle = scycle
/
SCYCLE LTRIM(SYS_CONNECT_BY_PATH(SDATE,','),',')
------ -----------------------------------------
M01 1,2
M02 1
Si vous êtes 11g, vous pouvez utiliser le haut- LISTAGG
fonction à la place:
with my_tabe as
(
select 'M01' as scycle, '1' as sdate from dual union
select 'M01' as scycle, '2' as sdate from dual union
select 'M02' as scycle, '1' as sdate from dual
)
select scycle, listagg (sdate, ',')
within group (order by sdate) res
from my_tabe
group by scycle
/
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