整数を書き数字に変換する
https://stackoverflow.com/questions/3213
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整数を表記された数値に変換する効率的な方法はありますか。たとえば、次のとおりです。
string Written = IntegerToWritten(21);
「Twenty One」を返します。
大規模なルックアップ テーブルを使用せずにこれを行う方法はありますか?
解決
これはかなりうまく機能するはずです。
public static class HumanFriendlyInteger
{
static string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
static string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
static string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
static string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };
private static string FriendlyInteger(int n, string leftDigits, int thousands)
{
if (n == 0)
{
return leftDigits;
}
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
{
friendlyInt += " ";
}
if (n < 10)
{
friendlyInt += ones[n];
}
else if (n < 20)
{
friendlyInt += teens[n - 10];
}
else if (n < 100)
{
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
}
else if (n < 1000)
{
friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
}
else
{
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);
if (n % 1000 == 0)
{
return friendlyInt;
}
}
return friendlyInt + thousandsGroups[thousands];
}
public static string IntegerToWritten(int n)
{
if (n == 0)
{
return "Zero";
}
else if (n < 0)
{
return "Negative " + IntegerToWritten(-n);
}
return FriendlyInteger(n, "", 0);
}
}
(百万、十億などのバグを修正するために編集されました)
他のヒント
私はHumanizerという便利なライブラリを使っています。
https://github.com/Humanizr/Humanizer
いくつかの文化をサポートしており、数値だけでなく日付も変換でき、使い方は非常に簡単です。
私の使い方は次のとおりです。
int someNumber = 543;
var culture = System.Globalization.CultureInfo("en-US");
var result = someNumber.ToWords(culture); // 543 -> five hundred forty-three
そして出来上がり！
私はこのコードを使用しています。これは VB コードですが、簡単に C# に変換できます。それは動作します
Function NumberToText(ByVal n As Integer) As String
Select Case n
Case 0
Return ""
Case 1 To 19
Dim arr() As String = {"One","Two","Three","Four","Five","Six","Seven", _
"Eight","Nine","Ten","Eleven","Twelve","Thirteen","Fourteen", _
"Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"}
Return arr(n-1) & " "
Case 20 to 99
Dim arr() as String = {"Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"}
Return arr(n\10 -2) & " " & NumberToText(n Mod 10)
Case 100 to 199
Return "One Hundred " & NumberToText(n Mod 100)
Case 200 to 999
Return NumberToText(n\100) & "Hundreds " & NumberToText(n mod 100)
Case 1000 to 1999
Return "One Thousand " & NumberToText(n Mod 1000)
Case 2000 to 999999
Return NumberToText(n\1000) & "Thousands " & NumberToText(n Mod 1000)
Case 1000000 to 1999999
Return "One Million " & NumberToText(n Mod 1000000)
Case 1000000 to 999999999
Return NumberToText(n\1000000) & "Millions " & NumberToText(n Mod 1000000)
Case 1000000000 to 1999999999
Return "One Billion " & NumberTotext(n Mod 1000000000)
Case Else
Return NumberToText(n\1000000000) & "Billion " _
& NumberToText(n mod 1000000000)
End Select
End Function
これがC#のコードです
public static string AmountInWords(double amount)
{
var n = (int)amount;
if (n == 0)
return "";
else if (n > 0 && n <= 19)
{
var arr = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
return arr[n - 1] + " ";
}
else if (n >= 20 && n <= 99)
{
var arr = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
return arr[n / 10 - 2] + " " + AmountInWords(n % 10);
}
else if (n >= 100 && n <= 199)
{
return "One Hundred " + AmountInWords(n % 100);
}
else if (n >= 200 && n <= 999)
{
return AmountInWords(n / 100) + "Hundred " + AmountInWords(n % 100);
}
else if (n >= 1000 && n <= 1999)
{
return "One Thousand " + AmountInWords(n % 1000);
}
else if (n >= 2000 && n <= 999999)
{
return AmountInWords(n / 1000) + "Thousand " + AmountInWords(n % 1000);
}
else if (n >= 1000000 && n <= 1999999)
{
return "One Million " + AmountInWords(n % 1000000);
}
else if (n >= 1000000 && n <= 999999999)
{
return AmountInWords(n / 1000000) + "Million " + AmountInWords(n % 1000000);
}
else if (n >= 1000000000 && n <= 1999999999)
{
return "One Billion " + AmountInWords(n % 1000000000);
}
else
{
return AmountInWords(n / 1000000000) + "Billion " + AmountInWords(n % 1000000000);
}
}
Justin Rogers には「NumbersToEnglish」クラスがあり、これがうまく機能するはずです。
初投稿。
http://weblogs.asp.net/justin_rogers/archive/2004/06/09/151675.aspx
最終的なソースコード
http://weblogs.asp.net/justin_rogers/articles/151757.aspx
ちょっとした内部ルックアップテーブルがありますが、どうすればそこから抜け出せるのかはわかりません。
なぜ大規模なルックアップテーブルなのか?
string GetWrittenInteger(int n)
{
string[] a = new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" }
string[] b = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" }
string[] c = new string[] {"Twenty", "Thirty", "Forty", "Sixty", "Seventy", "Eighty", "Ninety"};
string[] d = new string[] {"Hundred", "Thousand", "Million"}
string s = n.ToString();
for (int i = 0; i < s.Length; i++)
{
// logic (too lazy but you get the idea)
}
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace tryingstartfror4digits
{
class Program
{
static void Main(string[] args)
{
Program pg = new Program();
Console.WriteLine("Enter ur number");
int num = Convert.ToInt32(Console.ReadLine());
if (num <= 19)
{
string g = pg.first(num);
Console.WriteLine("The number is " + g);
}
else if ((num >= 20) && (num <= 99))
{
if (num % 10 == 0)
{
string g = pg.second(num / 10);
Console.WriteLine("The number is " + g);
}
else
{
string g = pg.second(num / 10) + pg.first(num % 10);
Console.WriteLine("The number is " + g);
}
}
else if ((num >= 100) && (num <= 999))
{
int k = num % 100;
string g = pg.first(num / 100) +pg.third(0) + pg.second(k / 10)+pg.first(k%10);
Console.WriteLine("The number is " + g);
}
else if ((num >= 1000) && (num <= 19999))
{
int h = num % 1000;
int k = h % 100;
string g = pg.first(num / 1000) + "Thousand " + pg.first(h/ 100) + pg.third(k) + pg.second(k / 10) + pg.first(k % 10);
Console.WriteLine("The number is " + g);
}
Console.ReadLine();
}
public string first(int num)
{
string name;
if (num == 0)
{
name = " ";
}
else
{
string[] arr1 = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" , "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
name = arr1[num - 1];
}
return name;
}
public string second(int num)
{
string name;
if ((num == 0)||(num==1))
{
name = " ";
}
else
{
string[] arr1 = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
name = arr1[num - 2];
}
return name;
}
public string third(int num)
{
string name ;
if (num == 0)
{
name = "";
}
else
{
string[] arr1 = new string[] { "Hundred" };
name = arr1[0];
}
return name;
}
}
}
1 から 19999 までは正常に動作します。完了したらすぐに更新されます
受け入れられた答えは完全に機能していないようです。21 のような数字のダッシュは処理されません。また、「101」のような数字に「and」という単語が挿入されません。そして、まあ、再帰的です。
これが私の答えです。「and」という単語をインテリジェントに追加し、数字を適切にハイフネーションします。変更が必要な場合はお知らせください。
これを呼び出す方法は次のとおりです (明らかに、これをクラスのどこかに置きたくなるでしょう)。
for (int i = int.MinValue+1; i < int.MaxValue; i++)
{
Console.WriteLine(ToWords(i));
}
コードは次のとおりです。
private static readonly string[] Ones = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};
private static readonly string[] Teens =
{
"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
"Seventeen", "Eighteen", "Nineteen"
};
private static readonly string[] Tens =
{
"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty",
"Ninety"
};
public static string ToWords(int number)
{
if (number == 0)
return "Zero";
var wordsList = new List<string>();
if (number < 0)
{
wordsList.Add("Negative");
number = Math.Abs(number);
}
if (number >= 1000000000 && number <= int.MaxValue) //billions
{
int billionsValue = number / 1000000000;
GetValuesUnder1000(billionsValue, wordsList);
wordsList.Add("Billion");
number -= billionsValue * 1000000000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
if (number >= 1000000 && number < 1000000000) //millions
{
int millionsValue = number / 1000000;
GetValuesUnder1000(millionsValue, wordsList);
wordsList.Add("Million");
number -= millionsValue * 1000000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
if (number >= 1000 && number < 1000000) //thousands
{
int thousandsValue = number/1000;
GetValuesUnder1000(thousandsValue, wordsList);
wordsList.Add("Thousand");
number -= thousandsValue * 1000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
GetValuesUnder1000(number, wordsList);
return string.Join(" ", wordsList);
}
private static void GetValuesUnder1000(int number, List<string> wordsList)
{
while (number != 0)
{
if (number < 10)
{
wordsList.Add(Ones[number]);
number -= number;
}
else if (number < 20)
{
wordsList.Add(Teens[number - 10]);
number -= number;
}
else if (number < 100)
{
int tensValue = ((int) (number/10))*10;
int onesValue = number - tensValue;
if (onesValue == 0)
{
wordsList.Add(Tens[tensValue/10]);
}
else
{
wordsList.Add(Tens[tensValue/10] + "-" + Ones[onesValue]);
}
number -= tensValue;
number -= onesValue;
}
else if (number < 1000)
{
int hundredsValue = ((int) (number/100))*100;
wordsList.Add(Ones[hundredsValue/100]);
wordsList.Add("Hundred");
number -= hundredsValue;
if (number > 0)
wordsList.Add("and");
}
}
}
がここにあります C# コンソール アプリケーション 小数点だけでなく整数も返します。
同じ問題のベンガル数字に対するニックマサオの回答の拡張です。数値の初期入力は Unicode 文字列です。乾杯！！
string number = "২২৮৯";
number = number.Replace("০", "0").Replace("১", "1").Replace("২", "2").Replace("৩", "3").Replace("৪", "4").Replace("৫", "5").Replace("৬", "6").Replace("৭", "7").Replace("৮", "8").Replace("৯", "9");
double vtempdbl = Convert.ToDouble(number);
string amount = AmountInWords(vtempdbl);
private static string AmountInWords(double amount)
{
var n = (int)amount;
if (n == 0)
return " ";
else if (n > 0 && n <= 99)
{
var arr = new string[] { "এক", "দুই", "তিন", "চার", "পাঁচ", "ছয়", "সাত", "আট", "নয়", "দশ", "এগার", "বারো", "তের", "চৌদ্দ", "পনের", "ষোল", "সতের", "আঠার", "ঊনিশ", "বিশ", "একুশ", "বাইস", "তেইশ", "চব্বিশ", "পঁচিশ", "ছাব্বিশ", "সাতাশ", "আঠাশ", "ঊনত্রিশ", "ত্রিশ", "একত্রিস", "বত্রিশ", "তেত্রিশ", "চৌত্রিশ", "পঁয়ত্রিশ", "ছত্রিশ", "সাঁইত্রিশ", "আটত্রিশ", "ঊনচল্লিশ", "চল্লিশ", "একচল্লিশ", "বিয়াল্লিশ", "তেতাল্লিশ", "চুয়াল্লিশ", "পয়তাল্লিশ", "ছিচল্লিশ", "সাতচল্লিশ", "আতচল্লিশ", "উনপঞ্চাশ", "পঞ্চাশ", "একান্ন", "বায়ান্ন", "তিপ্পান্ন", "চুয়ান্ন", "পঞ্চান্ন", "ছাপ্পান্ন", "সাতান্ন", "আটান্ন", "উনষাট", "ষাট", "একষট্টি", "বাষট্টি", "তেষট্টি", "চৌষট্টি", "পয়ষট্টি", "ছিষট্টি", " সাতষট্টি", "আটষট্টি", "ঊনসত্তর ", "সত্তর", "একাত্তর ", "বাহাত্তর", "তেহাত্তর", "চুয়াত্তর", "পঁচাত্তর", "ছিয়াত্তর", "সাতাত্তর", "আটাত্তর", "ঊনাশি", "আশি", "একাশি", "বিরাশি", "তিরাশি", "চুরাশি", "পঁচাশি", "ছিয়াশি", "সাতাশি", "আটাশি", "উননব্বই", "নব্বই", "একানব্বই", "বিরানব্বই", "তিরানব্বই", "চুরানব্বই", "পঁচানব্বই ", "ছিয়ানব্বই ", "সাতানব্বই", "আটানব্বই", "নিরানব্বই" };
return arr[n - 1] + " ";
}
else if (n >= 100 && n <= 199)
{
return AmountInWords(n / 100) + "এক শত " + AmountInWords(n % 100);
}
else if (n >= 100 && n <= 999)
{
return AmountInWords(n / 100) + "শত " + AmountInWords(n % 100);
}
else if (n >= 1000 && n <= 1999)
{
return "এক হাজার " + AmountInWords(n % 1000);
}
else if (n >= 1000 && n <= 99999)
{
return AmountInWords(n / 1000) + "হাজার " + AmountInWords(n % 1000);
}
else if (n >= 100000 && n <= 199999)
{
return "এক লাখ " + AmountInWords(n % 100000);
}
else if (n >= 100000 && n <= 9999999)
{
return AmountInWords(n / 100000) + "লাখ " + AmountInWords(n % 100000);
}
else if (n >= 10000000 && n <= 19999999)
{
return "এক কোটি " + AmountInWords(n % 10000000);
}
else
{
return AmountInWords(n / 10000000) + "কোটি " + AmountInWords(n % 10000000);
}
}
次の C# コンソール アプリ コードは、小数点第 2 位までの数値で金額を受け入れ、英語で出力します。これは、整数を英語の同等の値に変換するだけでなく、ドルとセントの通貨価値にも変換します。
namespace ConsoleApplication2
{
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
bool repeat = true;
while (repeat)
{
string inputMonetaryValueInNumberic = string.Empty;
string centPart = string.Empty;
string dollarPart = string.Empty;
Console.Write("\nEnter the monetary value : ");
inputMonetaryValueInNumberic = Console.ReadLine();
inputMonetaryValueInNumberic = inputMonetaryValueInNumberic.TrimStart('0');
if (ValidateInput(inputMonetaryValueInNumberic))
{
if (inputMonetaryValueInNumberic.Contains('.'))
{
centPart = ProcessCents(inputMonetaryValueInNumberic.Substring(inputMonetaryValueInNumberic.IndexOf(".") + 1));
dollarPart = ProcessDollar(inputMonetaryValueInNumberic.Substring(0, inputMonetaryValueInNumberic.IndexOf(".")));
}
else
{
dollarPart = ProcessDollar(inputMonetaryValueInNumberic);
}
centPart = string.IsNullOrWhiteSpace(centPart) ? string.Empty : " and " + centPart;
Console.WriteLine(string.Format("\n\n{0}{1}", dollarPart, centPart));
}
else
{
Console.WriteLine("Invalid Input..");
}
Console.WriteLine("\n\nPress any key to continue or Escape of close : ");
var loop = Console.ReadKey();
repeat = !loop.Key.ToString().Contains("Escape");
Console.Clear();
}
}
private static string ProcessCents(string cents)
{
string english = string.Empty;
string dig3 = Process3Digit(cents);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(0));
}
english = dig3 + english;
return english;
}
private static string ProcessDollar(string dollar)
{
string english = string.Empty;
foreach (var item in Get3DigitList(dollar))
{
string dig3 = Process3Digit(item.Value);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(item.Key));
}
english = dig3 + english;
}
return english;
}
private static string Process3Digit(string digit3)
{
string result = string.Empty;
if (Convert.ToInt32(digit3) != 0)
{
int place = 0;
Stack<string> monetaryValue = new Stack<string>();
for (int i = digit3.Length - 1; i >= 0; i--)
{
place += 1;
string stringValue = string.Empty;
switch (place)
{
case 1:
stringValue = GetOnes(digit3[i].ToString());
break;
case 2:
int tens = Convert.ToInt32(digit3[i]);
if (tens == 1)
{
if (monetaryValue.Count > 0)
{
monetaryValue.Pop();
}
stringValue = GetTens((digit3[i].ToString() + digit3[i + 1].ToString()));
}
else
{
stringValue = GetTens(digit3[i].ToString());
}
break;
case 3:
stringValue = GetOnes(digit3[i].ToString());
if (!string.IsNullOrWhiteSpace(stringValue))
{
string postFixWith = " Hundred";
if (monetaryValue.Count > 0)
{
postFixWith = postFixWith + " And";
}
stringValue += postFixWith;
}
break;
}
if (!string.IsNullOrWhiteSpace(stringValue))
monetaryValue.Push(stringValue);
}
while (monetaryValue.Count > 0)
{
result += " " + monetaryValue.Pop().ToString().Trim();
}
}
return result;
}
private static Dictionary<int, string> Get3DigitList(string monetaryValueInNumberic)
{
Dictionary<int, string> hundredsStack = new Dictionary<int, string>();
int counter = 0;
while (monetaryValueInNumberic.Length >= 3)
{
string digit3 = monetaryValueInNumberic.Substring(monetaryValueInNumberic.Length - 3, 3);
monetaryValueInNumberic = monetaryValueInNumberic.Substring(0, monetaryValueInNumberic.Length - 3);
hundredsStack.Add(++counter, digit3);
}
if (monetaryValueInNumberic.Length != 0)
hundredsStack.Add(++counter, monetaryValueInNumberic);
return hundredsStack;
}
private static string GetTens(string tensPlaceValue)
{
string englishEquvalent = string.Empty;
int value = Convert.ToInt32(tensPlaceValue);
Dictionary<int, string> tens = new Dictionary<int, string>();
tens.Add(2, "Twenty");
tens.Add(3, "Thirty");
tens.Add(4, "Forty");
tens.Add(5, "Fifty");
tens.Add(6, "Sixty");
tens.Add(7, "Seventy");
tens.Add(8, "Eighty");
tens.Add(9, "Ninty");
tens.Add(10, "Ten");
tens.Add(11, "Eleven");
tens.Add(12, "Twelve");
tens.Add(13, "Thrteen");
tens.Add(14, "Fourteen");
tens.Add(15, "Fifteen");
tens.Add(16, "Sixteen");
tens.Add(17, "Seventeen");
tens.Add(18, "Eighteen");
tens.Add(19, "Ninteen");
if (tens.ContainsKey(value))
{
englishEquvalent = tens[value];
}
return englishEquvalent;
}
private static string GetOnes(string onesPlaceValue)
{
int value = Convert.ToInt32(onesPlaceValue);
string englishEquvalent = string.Empty;
Dictionary<int, string> ones = new Dictionary<int, string>();
ones.Add(1, " One");
ones.Add(2, " Two");
ones.Add(3, " Three");
ones.Add(4, " Four");
ones.Add(5, " Five");
ones.Add(6, " Six");
ones.Add(7, " Seven");
ones.Add(8, " Eight");
ones.Add(9, " Nine");
if (ones.ContainsKey(value))
{
englishEquvalent = ones[value];
}
return englishEquvalent;
}
private static string GetSections(int section)
{
string sectionName = string.Empty;
switch (section)
{
case 0:
sectionName = "Cents";
break;
case 1:
sectionName = "Dollars";
break;
case 2:
sectionName = "Thousand";
break;
case 3:
sectionName = "Million";
break;
case 4:
sectionName = "Billion";
break;
case 5:
sectionName = "Trillion";
break;
case 6:
sectionName = "Zillion";
break;
}
return sectionName;
}
private static bool ValidateInput(string input)
{
return Regex.IsMatch(input, "[0-9]{1,18}(\\.[0-9]{1,2})?"))
}
}
}
その文字列を取得して、文字列s = txtnumber.text.toString（）のように同様に変換するだけです。int i=Convert.ToInt32(s.Tostring());完全な整数値のみを書き込みます
クラスのトルコ語表現のためだけに 人間に優しい整数 (↑) (テュルクチェ、セイヤズー カルシュルルジ):
public static class HumanFriendlyInteger
{
static string[] ones = new string[] { "", "Bir", "İki", "Üç", "Dört", "Beş", "Altı", "Yedi", "Sekiz", "Dokuz" };
static string[] teens = new string[] { "On", "On Bir", "On İki", "On Üç", "On Dört", "On Beş", "On Altı", "On Yedi", "On Sekiz", "On Dokuz" };
static string[] tens = new string[] { "Yirmi", "Otuz", "Kırk", "Elli", "Altmış", "Yetmiş", "Seksen", "Doksan" };
static string[] thousandsGroups = { "", " Bin", " Milyon", " Milyar" };
private static string FriendlyInteger(int n, string leftDigits, int thousands)
{
if (n == 0)
{
return leftDigits;
}
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
{
friendlyInt += " ";
}
if (n < 10)
friendlyInt += ones[n];
else if (n < 20)
friendlyInt += teens[n - 10];
else if (n < 100)
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
else if (n < 1000)
friendlyInt += FriendlyInteger(n % 100, ((n / 100 == 1 ? "" : ones[n / 100] + " ") + "Yüz"), 0); // Yüz 1 ile başlangıçta "Bir" kelimesini Türkçe'de almaz.
else
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands + 1), 0);
return friendlyInt + thousandsGroups[thousands];
}
public static string IntegerToWritten(int n)
{
if (n == 0)
return "Sıfır";
else if (n < 0)
return "Eksi " + IntegerToWritten(-n);
return FriendlyInteger(n, "", 0);
}
所属していません StackOverflow
