Converter números inteiros a escrita de números
https://stackoverflow.com/questions/3213
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RussianPergunta
Existe um método eficiente para a conversão de um número inteiro à escrita de números, por exemplo:
string Written = IntegerToWritten(21);
retornaria "Vinte e Um".
Existe alguma maneira de fazer isso que não envolvem uma enorme tabela look-up?
Solução
Isso deve funcionar razoavelmente bem:
public static class HumanFriendlyInteger
{
static string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
static string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
static string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
static string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };
private static string FriendlyInteger(int n, string leftDigits, int thousands)
{
if (n == 0)
{
return leftDigits;
}
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
{
friendlyInt += " ";
}
if (n < 10)
{
friendlyInt += ones[n];
}
else if (n < 20)
{
friendlyInt += teens[n - 10];
}
else if (n < 100)
{
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
}
else if (n < 1000)
{
friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
}
else
{
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);
if (n % 1000 == 0)
{
return friendlyInt;
}
}
return friendlyInt + thousandsGroups[thousands];
}
public static string IntegerToWritten(int n)
{
if (n == 0)
{
return "Zero";
}
else if (n < 0)
{
return "Negative " + IntegerToWritten(-n);
}
return FriendlyInteger(n, "", 0);
}
}
(Editado para corrigir um bug w/ milhão, bilhão, etc.)
Outras dicas
Eu uso este prático biblioteca chamada Humanizer.
https://github.com/Humanizr/Humanizer
Ele suporta várias culturas e converte não apenas números de palavras, mas também e é muito simples de usar.
Aqui está como eu uso:
int someNumber = 543;
var culture = System.Globalization.CultureInfo("en-US");
var result = someNumber.ToWords(culture); // 543 -> five hundred forty-three
E voilá!
Eu uso este código.Ele é de código VB, mas você pode facilmente traduzi-lo para C#.Ele funciona
Function NumberToText(ByVal n As Integer) As String
Select Case n
Case 0
Return ""
Case 1 To 19
Dim arr() As String = {"One","Two","Three","Four","Five","Six","Seven", _
"Eight","Nine","Ten","Eleven","Twelve","Thirteen","Fourteen", _
"Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"}
Return arr(n-1) & " "
Case 20 to 99
Dim arr() as String = {"Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"}
Return arr(n\10 -2) & " " & NumberToText(n Mod 10)
Case 100 to 199
Return "One Hundred " & NumberToText(n Mod 100)
Case 200 to 999
Return NumberToText(n\100) & "Hundreds " & NumberToText(n mod 100)
Case 1000 to 1999
Return "One Thousand " & NumberToText(n Mod 1000)
Case 2000 to 999999
Return NumberToText(n\1000) & "Thousands " & NumberToText(n Mod 1000)
Case 1000000 to 1999999
Return "One Million " & NumberToText(n Mod 1000000)
Case 1000000 to 999999999
Return NumberToText(n\1000000) & "Millions " & NumberToText(n Mod 1000000)
Case 1000000000 to 1999999999
Return "One Billion " & NumberTotext(n Mod 1000000000)
Case Else
Return NumberToText(n\1000000000) & "Billion " _
& NumberToText(n mod 1000000000)
End Select
End Function
Aqui está o código em c#
public static string AmountInWords(double amount)
{
var n = (int)amount;
if (n == 0)
return "";
else if (n > 0 && n <= 19)
{
var arr = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
return arr[n - 1] + " ";
}
else if (n >= 20 && n <= 99)
{
var arr = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
return arr[n / 10 - 2] + " " + AmountInWords(n % 10);
}
else if (n >= 100 && n <= 199)
{
return "One Hundred " + AmountInWords(n % 100);
}
else if (n >= 200 && n <= 999)
{
return AmountInWords(n / 100) + "Hundred " + AmountInWords(n % 100);
}
else if (n >= 1000 && n <= 1999)
{
return "One Thousand " + AmountInWords(n % 1000);
}
else if (n >= 2000 && n <= 999999)
{
return AmountInWords(n / 1000) + "Thousand " + AmountInWords(n % 1000);
}
else if (n >= 1000000 && n <= 1999999)
{
return "One Million " + AmountInWords(n % 1000000);
}
else if (n >= 1000000 && n <= 999999999)
{
return AmountInWords(n / 1000000) + "Million " + AmountInWords(n % 1000000);
}
else if (n >= 1000000000 && n <= 1999999999)
{
return "One Billion " + AmountInWords(n % 1000000000);
}
else
{
return AmountInWords(n / 1000000000) + "Billion " + AmountInWords(n % 1000000000);
}
}
Justin Rogers tem uma "NumbersToEnglish" classe, que devem fazer o trabalho para você muito bem!
Primeira postagem.
http://weblogs.asp.net/justin_rogers/archive/2004/06/09/151675.aspx
Finalizado O Código Fonte
http://weblogs.asp.net/justin_rogers/articles/151757.aspx
Ele tem um pouco de uma tabela de pesquisa interna, mas eu realmente não sei como você vai ser capaz de chegar longe.
por enorme tabela de pesquisa?
string GetWrittenInteger(int n)
{
string[] a = new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" }
string[] b = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" }
string[] c = new string[] {"Twenty", "Thirty", "Forty", "Sixty", "Seventy", "Eighty", "Ninety"};
string[] d = new string[] {"Hundred", "Thousand", "Million"}
string s = n.ToString();
for (int i = 0; i < s.Length; i++)
{
// logic (too lazy but you get the idea)
}
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace tryingstartfror4digits
{
class Program
{
static void Main(string[] args)
{
Program pg = new Program();
Console.WriteLine("Enter ur number");
int num = Convert.ToInt32(Console.ReadLine());
if (num <= 19)
{
string g = pg.first(num);
Console.WriteLine("The number is " + g);
}
else if ((num >= 20) && (num <= 99))
{
if (num % 10 == 0)
{
string g = pg.second(num / 10);
Console.WriteLine("The number is " + g);
}
else
{
string g = pg.second(num / 10) + pg.first(num % 10);
Console.WriteLine("The number is " + g);
}
}
else if ((num >= 100) && (num <= 999))
{
int k = num % 100;
string g = pg.first(num / 100) +pg.third(0) + pg.second(k / 10)+pg.first(k%10);
Console.WriteLine("The number is " + g);
}
else if ((num >= 1000) && (num <= 19999))
{
int h = num % 1000;
int k = h % 100;
string g = pg.first(num / 1000) + "Thousand " + pg.first(h/ 100) + pg.third(k) + pg.second(k / 10) + pg.first(k % 10);
Console.WriteLine("The number is " + g);
}
Console.ReadLine();
}
public string first(int num)
{
string name;
if (num == 0)
{
name = " ";
}
else
{
string[] arr1 = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" , "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
name = arr1[num - 1];
}
return name;
}
public string second(int num)
{
string name;
if ((num == 0)||(num==1))
{
name = " ";
}
else
{
string[] arr1 = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
name = arr1[num - 2];
}
return name;
}
public string third(int num)
{
string name ;
if (num == 0)
{
name = "";
}
else
{
string[] arr1 = new string[] { "Hundred" };
name = arr1[0];
}
return name;
}
}
}
isso funciona bem a partir de 1 de 19999 irá atualizar logo depois de eu completar
Aceito respostas não parecem funcionar perfeitamente.Ele não lidar com traços em números como vinte-e-um, de não colocar a palavra "e" para números como "cento e um", e, bem, ele é recursiva.
Aqui é o meu tiro na resposta.Ele acrescenta que "e" palavra de forma inteligente, e hifeniza as de números de forma adequada.Deixe-me saber se a quaisquer modificações são necessárias.
Aqui é como chamá-lo (obviamente, você vai querer colocar isso em uma classe em algum lugar):
for (int i = int.MinValue+1; i < int.MaxValue; i++)
{
Console.WriteLine(ToWords(i));
}
Aqui está o código:
private static readonly string[] Ones = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};
private static readonly string[] Teens =
{
"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
"Seventeen", "Eighteen", "Nineteen"
};
private static readonly string[] Tens =
{
"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty",
"Ninety"
};
public static string ToWords(int number)
{
if (number == 0)
return "Zero";
var wordsList = new List<string>();
if (number < 0)
{
wordsList.Add("Negative");
number = Math.Abs(number);
}
if (number >= 1000000000 && number <= int.MaxValue) //billions
{
int billionsValue = number / 1000000000;
GetValuesUnder1000(billionsValue, wordsList);
wordsList.Add("Billion");
number -= billionsValue * 1000000000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
if (number >= 1000000 && number < 1000000000) //millions
{
int millionsValue = number / 1000000;
GetValuesUnder1000(millionsValue, wordsList);
wordsList.Add("Million");
number -= millionsValue * 1000000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
if (number >= 1000 && number < 1000000) //thousands
{
int thousandsValue = number/1000;
GetValuesUnder1000(thousandsValue, wordsList);
wordsList.Add("Thousand");
number -= thousandsValue * 1000;
if (number > 0 && number < 10)
wordsList.Add("and");
}
GetValuesUnder1000(number, wordsList);
return string.Join(" ", wordsList);
}
private static void GetValuesUnder1000(int number, List<string> wordsList)
{
while (number != 0)
{
if (number < 10)
{
wordsList.Add(Ones[number]);
number -= number;
}
else if (number < 20)
{
wordsList.Add(Teens[number - 10]);
number -= number;
}
else if (number < 100)
{
int tensValue = ((int) (number/10))*10;
int onesValue = number - tensValue;
if (onesValue == 0)
{
wordsList.Add(Tens[tensValue/10]);
}
else
{
wordsList.Add(Tens[tensValue/10] + "-" + Ones[onesValue]);
}
number -= tensValue;
number -= onesValue;
}
else if (number < 1000)
{
int hundredsValue = ((int) (number/100))*100;
wordsList.Add(Ones[hundredsValue/100]);
wordsList.Add("Hundred");
number -= hundredsValue;
if (number > 0)
wordsList.Add("and");
}
}
}
Aqui é um C# Aplicativo De Console que irá devolver todo o números de casas decimais.
Uma extensão de Nick Masao a resposta para o Bengali Numérico do mesmo problema.Primeiro de entrada de número na seqüência de caracteres Unicode.Cheers!!
string number = "২২৮৯";
number = number.Replace("০", "0").Replace("১", "1").Replace("২", "2").Replace("৩", "3").Replace("৪", "4").Replace("৫", "5").Replace("৬", "6").Replace("৭", "7").Replace("৮", "8").Replace("৯", "9");
double vtempdbl = Convert.ToDouble(number);
string amount = AmountInWords(vtempdbl);
private static string AmountInWords(double amount)
{
var n = (int)amount;
if (n == 0)
return " ";
else if (n > 0 && n <= 99)
{
var arr = new string[] { "এক", "দুই", "তিন", "চার", "পাঁচ", "ছয়", "সাত", "আট", "নয়", "দশ", "এগার", "বারো", "তের", "চৌদ্দ", "পনের", "ষোল", "সতের", "আঠার", "ঊনিশ", "বিশ", "একুশ", "বাইস", "তেইশ", "চব্বিশ", "পঁচিশ", "ছাব্বিশ", "সাতাশ", "আঠাশ", "ঊনত্রিশ", "ত্রিশ", "একত্রিস", "বত্রিশ", "তেত্রিশ", "চৌত্রিশ", "পঁয়ত্রিশ", "ছত্রিশ", "সাঁইত্রিশ", "আটত্রিশ", "ঊনচল্লিশ", "চল্লিশ", "একচল্লিশ", "বিয়াল্লিশ", "তেতাল্লিশ", "চুয়াল্লিশ", "পয়তাল্লিশ", "ছিচল্লিশ", "সাতচল্লিশ", "আতচল্লিশ", "উনপঞ্চাশ", "পঞ্চাশ", "একান্ন", "বায়ান্ন", "তিপ্পান্ন", "চুয়ান্ন", "পঞ্চান্ন", "ছাপ্পান্ন", "সাতান্ন", "আটান্ন", "উনষাট", "ষাট", "একষট্টি", "বাষট্টি", "তেষট্টি", "চৌষট্টি", "পয়ষট্টি", "ছিষট্টি", " সাতষট্টি", "আটষট্টি", "ঊনসত্তর ", "সত্তর", "একাত্তর ", "বাহাত্তর", "তেহাত্তর", "চুয়াত্তর", "পঁচাত্তর", "ছিয়াত্তর", "সাতাত্তর", "আটাত্তর", "ঊনাশি", "আশি", "একাশি", "বিরাশি", "তিরাশি", "চুরাশি", "পঁচাশি", "ছিয়াশি", "সাতাশি", "আটাশি", "উননব্বই", "নব্বই", "একানব্বই", "বিরানব্বই", "তিরানব্বই", "চুরানব্বই", "পঁচানব্বই ", "ছিয়ানব্বই ", "সাতানব্বই", "আটানব্বই", "নিরানব্বই" };
return arr[n - 1] + " ";
}
else if (n >= 100 && n <= 199)
{
return AmountInWords(n / 100) + "এক শত " + AmountInWords(n % 100);
}
else if (n >= 100 && n <= 999)
{
return AmountInWords(n / 100) + "শত " + AmountInWords(n % 100);
}
else if (n >= 1000 && n <= 1999)
{
return "এক হাজার " + AmountInWords(n % 1000);
}
else if (n >= 1000 && n <= 99999)
{
return AmountInWords(n / 1000) + "হাজার " + AmountInWords(n % 1000);
}
else if (n >= 100000 && n <= 199999)
{
return "এক লাখ " + AmountInWords(n % 100000);
}
else if (n >= 100000 && n <= 9999999)
{
return AmountInWords(n / 100000) + "লাখ " + AmountInWords(n % 100000);
}
else if (n >= 10000000 && n <= 19999999)
{
return "এক কোটি " + AmountInWords(n % 10000000);
}
else
{
return AmountInWords(n / 10000000) + "কোটি " + AmountInWords(n % 10000000);
}
}
O seguinte C# aplicativo de console de código será aceita um valor monetário em números com até 2 casas decimais e imprime em inglês.Isto não só converte inteiro para o seu equivalente em inglês, mas como um valor monetário em dólares e centavos.
namespace ConsoleApplication2
{
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
bool repeat = true;
while (repeat)
{
string inputMonetaryValueInNumberic = string.Empty;
string centPart = string.Empty;
string dollarPart = string.Empty;
Console.Write("\nEnter the monetary value : ");
inputMonetaryValueInNumberic = Console.ReadLine();
inputMonetaryValueInNumberic = inputMonetaryValueInNumberic.TrimStart('0');
if (ValidateInput(inputMonetaryValueInNumberic))
{
if (inputMonetaryValueInNumberic.Contains('.'))
{
centPart = ProcessCents(inputMonetaryValueInNumberic.Substring(inputMonetaryValueInNumberic.IndexOf(".") + 1));
dollarPart = ProcessDollar(inputMonetaryValueInNumberic.Substring(0, inputMonetaryValueInNumberic.IndexOf(".")));
}
else
{
dollarPart = ProcessDollar(inputMonetaryValueInNumberic);
}
centPart = string.IsNullOrWhiteSpace(centPart) ? string.Empty : " and " + centPart;
Console.WriteLine(string.Format("\n\n{0}{1}", dollarPart, centPart));
}
else
{
Console.WriteLine("Invalid Input..");
}
Console.WriteLine("\n\nPress any key to continue or Escape of close : ");
var loop = Console.ReadKey();
repeat = !loop.Key.ToString().Contains("Escape");
Console.Clear();
}
}
private static string ProcessCents(string cents)
{
string english = string.Empty;
string dig3 = Process3Digit(cents);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(0));
}
english = dig3 + english;
return english;
}
private static string ProcessDollar(string dollar)
{
string english = string.Empty;
foreach (var item in Get3DigitList(dollar))
{
string dig3 = Process3Digit(item.Value);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(item.Key));
}
english = dig3 + english;
}
return english;
}
private static string Process3Digit(string digit3)
{
string result = string.Empty;
if (Convert.ToInt32(digit3) != 0)
{
int place = 0;
Stack<string> monetaryValue = new Stack<string>();
for (int i = digit3.Length - 1; i >= 0; i--)
{
place += 1;
string stringValue = string.Empty;
switch (place)
{
case 1:
stringValue = GetOnes(digit3[i].ToString());
break;
case 2:
int tens = Convert.ToInt32(digit3[i]);
if (tens == 1)
{
if (monetaryValue.Count > 0)
{
monetaryValue.Pop();
}
stringValue = GetTens((digit3[i].ToString() + digit3[i + 1].ToString()));
}
else
{
stringValue = GetTens(digit3[i].ToString());
}
break;
case 3:
stringValue = GetOnes(digit3[i].ToString());
if (!string.IsNullOrWhiteSpace(stringValue))
{
string postFixWith = " Hundred";
if (monetaryValue.Count > 0)
{
postFixWith = postFixWith + " And";
}
stringValue += postFixWith;
}
break;
}
if (!string.IsNullOrWhiteSpace(stringValue))
monetaryValue.Push(stringValue);
}
while (monetaryValue.Count > 0)
{
result += " " + monetaryValue.Pop().ToString().Trim();
}
}
return result;
}
private static Dictionary<int, string> Get3DigitList(string monetaryValueInNumberic)
{
Dictionary<int, string> hundredsStack = new Dictionary<int, string>();
int counter = 0;
while (monetaryValueInNumberic.Length >= 3)
{
string digit3 = monetaryValueInNumberic.Substring(monetaryValueInNumberic.Length - 3, 3);
monetaryValueInNumberic = monetaryValueInNumberic.Substring(0, monetaryValueInNumberic.Length - 3);
hundredsStack.Add(++counter, digit3);
}
if (monetaryValueInNumberic.Length != 0)
hundredsStack.Add(++counter, monetaryValueInNumberic);
return hundredsStack;
}
private static string GetTens(string tensPlaceValue)
{
string englishEquvalent = string.Empty;
int value = Convert.ToInt32(tensPlaceValue);
Dictionary<int, string> tens = new Dictionary<int, string>();
tens.Add(2, "Twenty");
tens.Add(3, "Thirty");
tens.Add(4, "Forty");
tens.Add(5, "Fifty");
tens.Add(6, "Sixty");
tens.Add(7, "Seventy");
tens.Add(8, "Eighty");
tens.Add(9, "Ninty");
tens.Add(10, "Ten");
tens.Add(11, "Eleven");
tens.Add(12, "Twelve");
tens.Add(13, "Thrteen");
tens.Add(14, "Fourteen");
tens.Add(15, "Fifteen");
tens.Add(16, "Sixteen");
tens.Add(17, "Seventeen");
tens.Add(18, "Eighteen");
tens.Add(19, "Ninteen");
if (tens.ContainsKey(value))
{
englishEquvalent = tens[value];
}
return englishEquvalent;
}
private static string GetOnes(string onesPlaceValue)
{
int value = Convert.ToInt32(onesPlaceValue);
string englishEquvalent = string.Empty;
Dictionary<int, string> ones = new Dictionary<int, string>();
ones.Add(1, " One");
ones.Add(2, " Two");
ones.Add(3, " Three");
ones.Add(4, " Four");
ones.Add(5, " Five");
ones.Add(6, " Six");
ones.Add(7, " Seven");
ones.Add(8, " Eight");
ones.Add(9, " Nine");
if (ones.ContainsKey(value))
{
englishEquvalent = ones[value];
}
return englishEquvalent;
}
private static string GetSections(int section)
{
string sectionName = string.Empty;
switch (section)
{
case 0:
sectionName = "Cents";
break;
case 1:
sectionName = "Dollars";
break;
case 2:
sectionName = "Thousand";
break;
case 3:
sectionName = "Million";
break;
case 4:
sectionName = "Billion";
break;
case 5:
sectionName = "Trillion";
break;
case 6:
sectionName = "Zillion";
break;
}
return sectionName;
}
private static bool ValidateInput(string input)
{
return Regex.IsMatch(input, "[0-9]{1,18}(\\.[0-9]{1,2})?"))
}
}
}
só chegar que a seqüência de caracteres e converter com a como string s=txtNumber.Texto.Tostring();int i=Converter.ToInt32(s.Tostring());ele vai escrever apenas o valor inteiro
Apenas para turco representação da classe HumanFriendlyInteger (↑) (Türkçe, sayı yazı karşılığı):
public static class HumanFriendlyInteger
{
static string[] ones = new string[] { "", "Bir", "İki", "Üç", "Dört", "Beş", "Altı", "Yedi", "Sekiz", "Dokuz" };
static string[] teens = new string[] { "On", "On Bir", "On İki", "On Üç", "On Dört", "On Beş", "On Altı", "On Yedi", "On Sekiz", "On Dokuz" };
static string[] tens = new string[] { "Yirmi", "Otuz", "Kırk", "Elli", "Altmış", "Yetmiş", "Seksen", "Doksan" };
static string[] thousandsGroups = { "", " Bin", " Milyon", " Milyar" };
private static string FriendlyInteger(int n, string leftDigits, int thousands)
{
if (n == 0)
{
return leftDigits;
}
string friendlyInt = leftDigits;
if (friendlyInt.Length > 0)
{
friendlyInt += " ";
}
if (n < 10)
friendlyInt += ones[n];
else if (n < 20)
friendlyInt += teens[n - 10];
else if (n < 100)
friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
else if (n < 1000)
friendlyInt += FriendlyInteger(n % 100, ((n / 100 == 1 ? "" : ones[n / 100] + " ") + "Yüz"), 0); // Yüz 1 ile başlangıçta "Bir" kelimesini Türkçe'de almaz.
else
friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands + 1), 0);
return friendlyInt + thousandsGroups[thousands];
}
public static string IntegerToWritten(int n)
{
if (n == 0)
return "Sıfır";
else if (n < 0)
return "Eksi " + IntegerToWritten(-n);
return FriendlyInteger(n, "", 0);
}
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