SQL column4のデコードが、COLUMN5は別個のものであるのみ

Question

私は

のようなものの和（デコード（））式を変更する必要があります

SUM(Decode(vcon.WAGON_TYPE_CODE,'MS',1,0)) 

vcon.WAGON-TYPE-CODE = 'MS' はと行をカウントし、何かにwag.ACI-TAG-NOは別個のものであるときにのみます。

二つの列は次のようになりのであれば、

vcon.WAGON_TYPE_CODE   wag.ACI_TAG_NO 
MS                     HI1111 
SS                     C99999 
MS                     HI1111
MS                     HI7777
SS                     HI8888
MS                     HI6666

の発現は現在ないSUM（デコード（vcon.WAGON_TYPE_CODE、 'MS'、1,0））として数3なく4を返す必要があります。

任意の提案ですか？

querySELECT = "SELECT "
querySELECT = querySELECT & "trn.WID_DATE, "
querySELECT = querySELECT & "trn.MINE_CODE, "
querySELECT = querySELECT & "trn.TRAIN_CONTROL_ID, "
querySELECT = querySELECT & "trn.NUM_CARS as HBD_Car_Count, "
querySELECT = querySELECT & "SUM(Decode(vcon.WAGON_TYPE_CODE,'MS',1,0)) M_Series, "
querySELECT = querySELECT & "(SUM(Decode(vcon.WAGON_TYPE_CODE,'SS',1,0))-SUM(Decode(wag.ACI_TAG_NO,'HI0000',1,0))) S_Series, "
querySELECT = querySELECT & "SUM(Decode(vcon.WAGON_TYPE_CODE,'CS',1,0)) C_Series, "
querySELECT = querySELECT & "SUM(Decode(wag.ACI_TAG_NO,'HI0000',1,0)) as No_Tag, "
querySELECT = querySELECT & "(COUNT(1) - trn.NUM_CARS) DB_Mismatch "

queryFROM = "FROM widsys.consist con, widsys.train trn, widsys.wagon wag, widsys.v_consist_ore_detail vcon "

queryWHERE = "WHERE trn.TRAIN_RECORD_ID = con.TRAIN_RECORD_ID "
queryWHERE = queryWHERE & "AND con.WAGON_ID = wag.WAGON_ID "
queryWHERE = queryWHERE & "AND ((vcon.CONSIST_ID=con.CONSIST_ID) "
queryWHERE = queryWHERE & "AND trn.MINE_CODE In (" & mine & ") "
queryWHERE = queryWHERE & "AND (trn.DIRECTION='N') "
queryWHERE = queryWHERE & "AND (wag.ACI_TAG_TYPE In ('CONTROL','SLAVE','ORE')) "
queryWHERE = queryWHERE & "AND (trn.WID_DATE>={ts '" & startDate & "'} "
queryWHERE = queryWHERE & "AND trn.WID_DATE<={ts '" & endDate & "'})) "

queryGROUPBY = "GROUP BY trn.WID_DATE, trn.MINE_CODE, trn.TRAIN_CONTROL_ID, trn.NUM_CARS "
queryORDERBY = "ORDER BY trn.WID_DATE DESC"

Answer 1

私は（これが唯一の明確なwag.ACI_TAG_NOを数えるときvcon.WAGON_TYPE_CODE='MS'）以下は動作するはずだと思う。

COUNT(DISTINCT Decode(vcon.WAGON_TYPE_CODE,'MS',wag.ACI_TAG_NO,NULL))

E-G

SQL> WITH data AS (
  2     SELECT 'MS' WAGON_TYPE_CODE, 'HI1111' ACI_TAG_NO FROM DUAL UNION ALL
  3     SELECT 'SS', 'C99999' FROM DUAL UNION ALL
  4     SELECT 'MS', 'HI1111' FROM DUAL UNION ALL
  5     SELECT 'MS', 'HI7777' FROM DUAL UNION ALL
  6     SELECT 'SS', 'HI8888' FROM DUAL UNION ALL
  7     SELECT 'MS', 'HI6666' FROM DUAL
  8  )
  9  SELECT COUNT(DISTINCT decode(WAGON_TYPE_CODE,'MS',ACI_TAG_NO,NULL))
 10    FROM DATA
 11  ;

COUNT(DISTINCTDECODE(WAGON_TYP
------------------------------
                             3

乾杯、

-
ヴィンセント

Answer 2

あなたは重複タグをフィルタリングサブクエリを使用することができます。あなたのクエリはかなり複雑ですが、これはあなたが探しているだけの合計を計算します。

SELECT SUM(Decode(sub.WAGON_TYPE_CODE,'MS',1,0))
FROM (
    SELECT DISTINCT vcon.WAGON_TYPE_CODE, wag.ACI_TAG_NO
    FROM widsys.wagon wag
    INNER JOIN widsys.consist con 
        ON con.wagon_id = wag.wagon_id
    INNER JOIN widsys.v_consist_ore_detail vcon
        ON vcon.CONSIST_ID = con.CONSIST_ID
) sub

DISTINCTは（wagon_type、aci_tag_no）の組み合わせごとに1つだけの行があると確認します。