Column4에서 SQL Decode 그러나 Column5가 별개 일 때만

Question

Sum (decode ()) 표현식을 변경해야합니다.

SUM(Decode(vcon.WAGON_TYPE_CODE,'MS',1,0)) 

vcon.wagon-type-code = 'ms'로 행을 계산하는 것에 대해서만 wag.aci-tag-no가 뚜렷 할 때만.

따라서 두 열이 다음과 같이 보입니다

vcon.WAGON_TYPE_CODE   wag.ACI_TAG_NO 
MS                     HI1111 
SS                     C99999 
MS                     HI1111
MS                     HI7777
SS                     HI8888
MS                     HI6666

표현식은 현재 4가 아닌 4가 아닌 숫자 3을 반환해야합니다 (decode (vcon.wagon_type_code, 'ms', 1,0))는 현재합니다.

제안이 있습니까?

querySELECT = "SELECT "
querySELECT = querySELECT & "trn.WID_DATE, "
querySELECT = querySELECT & "trn.MINE_CODE, "
querySELECT = querySELECT & "trn.TRAIN_CONTROL_ID, "
querySELECT = querySELECT & "trn.NUM_CARS as HBD_Car_Count, "
querySELECT = querySELECT & "SUM(Decode(vcon.WAGON_TYPE_CODE,'MS',1,0)) M_Series, "
querySELECT = querySELECT & "(SUM(Decode(vcon.WAGON_TYPE_CODE,'SS',1,0))-SUM(Decode(wag.ACI_TAG_NO,'HI0000',1,0))) S_Series, "
querySELECT = querySELECT & "SUM(Decode(vcon.WAGON_TYPE_CODE,'CS',1,0)) C_Series, "
querySELECT = querySELECT & "SUM(Decode(wag.ACI_TAG_NO,'HI0000',1,0)) as No_Tag, "
querySELECT = querySELECT & "(COUNT(1) - trn.NUM_CARS) DB_Mismatch "

queryFROM = "FROM widsys.consist con, widsys.train trn, widsys.wagon wag, widsys.v_consist_ore_detail vcon "

queryWHERE = "WHERE trn.TRAIN_RECORD_ID = con.TRAIN_RECORD_ID "
queryWHERE = queryWHERE & "AND con.WAGON_ID = wag.WAGON_ID "
queryWHERE = queryWHERE & "AND ((vcon.CONSIST_ID=con.CONSIST_ID) "
queryWHERE = queryWHERE & "AND trn.MINE_CODE In (" & mine & ") "
queryWHERE = queryWHERE & "AND (trn.DIRECTION='N') "
queryWHERE = queryWHERE & "AND (wag.ACI_TAG_TYPE In ('CONTROL','SLAVE','ORE')) "
queryWHERE = queryWHERE & "AND (trn.WID_DATE>={ts '" & startDate & "'} "
queryWHERE = queryWHERE & "AND trn.WID_DATE<={ts '" & endDate & "'})) "

queryGROUPBY = "GROUP BY trn.WID_DATE, trn.MINE_CODE, trn.TRAIN_CONTROL_ID, trn.NUM_CARS "
queryORDERBY = "ORDER BY trn.WID_DATE DESC"

Answer 1

다음이 작동해야한다고 생각합니다 (이것은 별개 wag.ACI_TAG_NO 일 때만 vcon.WAGON_TYPE_CODE='MS') :

COUNT(DISTINCT Decode(vcon.WAGON_TYPE_CODE,'MS',wag.ACI_TAG_NO,NULL))

예 :

SQL> WITH data AS (
  2     SELECT 'MS' WAGON_TYPE_CODE, 'HI1111' ACI_TAG_NO FROM DUAL UNION ALL
  3     SELECT 'SS', 'C99999' FROM DUAL UNION ALL
  4     SELECT 'MS', 'HI1111' FROM DUAL UNION ALL
  5     SELECT 'MS', 'HI7777' FROM DUAL UNION ALL
  6     SELECT 'SS', 'HI8888' FROM DUAL UNION ALL
  7     SELECT 'MS', 'HI6666' FROM DUAL
  8  )
  9  SELECT COUNT(DISTINCT decode(WAGON_TYPE_CODE,'MS',ACI_TAG_NO,NULL))
 10    FROM DATA
 11  ;

COUNT(DISTINCTDECODE(WAGON_TYP
------------------------------
                             3

건배,

--
빈센트

Answer 2

중복 태그를 필터링하는 하위 쿼리를 사용할 수 있습니다. 쿼리는 꽤 복잡하지만 원하는 금액 만 계산합니다.

SELECT SUM(Decode(sub.WAGON_TYPE_CODE,'MS',1,0))
FROM (
    SELECT DISTINCT vcon.WAGON_TYPE_CODE, wag.ACI_TAG_NO
    FROM widsys.wagon wag
    INNER JOIN widsys.consist con 
        ON con.wagon_id = wag.wagon_id
    INNER JOIN widsys.v_consist_ore_detail vcon
        ON vcon.CONSIST_ID = con.CONSIST_ID
) sub

별개의 경우 (wagon_type, aci_tag_no) 조합 당 하나의 행만 있는지 확인합니다.