Splitting a list into two seperate lists, by every other item in python

StackOverflow https://stackoverflow.com/questions/22162074

  •  19-10-2022
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Вопрос

Hello I have a quick question I cant seem to solve.

I have a list:

a = [item1, item2, item3, item4, item5, item6]

And I want to split this list into two seperate ones by everything other item such that:

b = [item1, item3, item5]
c = [item2, item4, item6]

Нет правильного решения

Другие советы

Use slicing, specifying a step:

b,c = a[::2], a[1::2]

Using filter is one option:

a = [item1, item2, item3, item4, item5, item6]
b = filter(lambda x: a.index(x) % 2 == 0, a)
c = filter(lambda x: a.index(x) % 2 != 0, a)

EDIT: This would require for the elements to be unique and is inefficient.

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