当使用Hibernate Envers时，什么可能导致怪异的属性解决错误？

Question

可能导致休眠的方法试图解决软件包路径并在这样做时失败：

Exception in thread "Timer-9" org.hibernate.QueryException: could not resolve property: codeto of: citylist_AUD [select new list(ee, e) from citylist_AUD ee, ee.codeto.wes.Citylist_AUD e where ee.originalId.citylist_id = e.originalId.id and ee.originalId.Road_id = :Road_id and e.originalId.REV.id = (select max(e2.originalId.REV.id) from ee.codeto.wes.Citylist_AUD e2 where e2.originalId.REV.id <= :revision and e.originalId.id = e2.originalId.id) and ee.originalId.REV.id = (select max(ee2.originalId.REV.id) from road_city_AUD ee2 where ee2.originalId.REV.id <= :revision and ee.originalId.Road_id = ee2.originalId.Road_id and ee.originalId.citylist_id = ee2.originalId.citylist_id) and ee.REVTYPE != :delrevisiontype and e.REVTYPE != :delrevisiontype]
at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:81)
at org.hibernate.persister.entity.AbstractPropertyMapping.toType(AbstractPropertyMapping.java:75)
at org.hibernate.persister.entity.AbstractEntityPersister.toType(AbstractEntityPersister.java:1465)
at org.hibernate.hql.ast.tree.FromElementType.getPropertyType(FromElementType.java:315)
at org.hibernate.hql.ast.tree.FromElement.getPropertyType(FromElement.java:487)
at org.hibernate.hql.ast.tree.DotNode.getDataType(DotNode.java:611)
at org.hibernate.hql.ast.tree.DotNode.prepareLhs(DotNode.java:263)
at org.hibernate.hql.ast.tree.DotNode.resolve(DotNode.java:210)
at org.hibernate.hql.ast.tree.FromReferenceNode.recursiveResolve(FromReferenceNode.java:101)
at org.hibernate.hql.ast.tree.FromReferenceNode.recursiveResolve(FromReferenceNode.java:94)
at org.hibernate.hql.ast.tree.FromReferenceNode.recursiveResolve(FromReferenceNode.java:94)
at org.hibernate.hql.ast.tree.FromReferenceNode.recursiveResolve(FromReferenceNode.java:94)
at org.hibernate.hql.ast.tree.FromReferenceNode.recursiveResolve(FromReferenceNode.java:94)
at org.hibernate.hql.ast.tree.FromElementFactory.evaluateFromElementPath(FromElementFactory.java:172)
at org.hibernate.hql.ast.tree.FromElementFactory.createFromElementInSubselect(FromElementFactory.java:134)
at org.hibernate.hql.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:107)
at org.hibernate.hql.ast.tree.FromClause.addFromElement(FromClause.java:93)
at org.hibernate.hql.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:327)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3441)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3325)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:733)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:584)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.exprOrSubquery(HqlSqlBaseWalker.java:4479)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.comparisonExpr(HqlSqlBaseWalker.java:3947)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2047)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:1975)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:1972)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:1972)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:1972)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.whereClause(HqlSqlBaseWalker.java:831)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:617)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:301)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:244)
at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:256)
at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:187)
at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:138)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80)
at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:124)
at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:156)
at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:135)
at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1770)
at org.hibernate.envers.entities.mapper.relation.query.TwoEntityQueryGenerator.getQuery(TwoEntityQueryGenerator.java:128)
at org.hibernate.envers.entities.mapper.relation.lazy.initializor.AbstractCollectionInitializor.initialize(AbstractCollectionInitializor.java:62)
at org.hibernate.envers.entities.mapper.relation.lazy.proxy.CollectionProxy.checkInit(CollectionProxy.java:50)
at org.hibernate.envers.entities.mapper.relation.lazy.proxy.CollectionProxy.iterator(CollectionProxy.java:70)
at ee.codeto.wes.Helper.getListSum(Helper.java:329)

我正在使用冬眠3.6.9

一切都在起作用，直到我介绍了两个被审计实体之间的Manytomany关系的审计。基本上是java：

@Audited
@Entity
@Table(name = "ROAD")
@Cache(usage = CacheConcurrencyStrategy.READ_WRITE)
public class Road {
    ...
    @Audited(targetAuditMode = RelationTargetAuditMode.NOT_AUDITED)
    @ManyToMany(fetch = FetchType.LAZY)
    @JoinTable(name = "ROAD_CITYLIST", joinColumns = { @JoinColumn(name = "ROAD_ID") }, inverseJoinColumns = { @JoinColumn(name = "CITYLIST_ID") })
    @Fetch(FetchMode.SUBSELECT)
    @Cache(usage = CacheConcurrencyStrategy.NONE)
    private Set<CityList> citylists;
    ...
}

我以相同的逻辑进行了类似的较小测试，并取得了成功。我真的很感激任何帮助或向正确方向推动的帮助。如果需要其他信息，请命名，我可以提供。

Answer 1

回答我自己的问题：

该错误是用3.6的Hibernate Envers使用的，在某些情况下，它遇到了来自爱沙尼亚域名的软件包名称（例如ee.codeto.foo）。这是因为在构建“ ee”的构建过程中的某个时刻，Hibernate Envers作为别名，并且使用包裹的完整名称（现在总是），然后Hibernate认为，在包装名称中的下一个部分是“ EE” “是列名。

在冬眠的后期版本中，解决了这个问题。可能不是因为爱沙尼亚域名的名称，而是由于更好的别名使用情况。 “ ee_“使用而不是“ ee”。因此，当您可能不幸的是与“ EE”包裹不幸时_“作为包装名称的第一部分，碰巧使用Hibernate Envers并碰巧使用多对多的映射，并且碰巧的是Hibernet试图使用包装的完整班级名称的不幸情况您可能会受到此错误的限制。