简单透明例如Java的3D不工作
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21-08-2019 - |
题
我在J3D一个完整的n00b(但在Java方面的专家)。刚开始,我正在与透明度玩的问题。我有一个简单的例子,其绘制的旋转平面的四(表示背面时,因为我有未禁用背面剔除消失)。
使用的Color3b和COLOR_3线未注释(以及相应的Color4b和COLOR_4线注释),我看到旋转四,着色为红色。
然而,当我评论颜色-3线路,并取消对彩色4行,我看到黑色正方形(对白色背景),即使阿尔法值被设定为255(完全不透明)。
我在做什么错了?谷歌没有帮助,甚至Java3D的论坛上,在java.forums.net小于很有帮助。 StackOverflow的,救我!您可以复制和过去的下面的程序,运行它,看看会发生什么。
下面是我的规格:
在OSX 10.5.5 Java 6的 J3D 1.5.2 JOGL 1.1.1
谢谢,
- 罗布
下面的代码:
import com.sun.j3d.utils.applet.MainFrame;
import com.sun.j3d.utils.geometry.ColorCube;
import com.sun.j3d.utils.universe.SimpleUniverse;
import java.applet.Applet;
import java.awt.*;
import javax.media.j3d.*;
import javax.vecmath.*;
public class Hello extends Applet
{
public Hello() throws Exception
{
setLayout(new BorderLayout());
GraphicsConfiguration config = SimpleUniverse.getPreferredConfiguration();
Canvas3D canvas3D = new Canvas3D(config);
add("Center", canvas3D);
BranchGroup scene = createSceneGraph();
scene.compile();
SimpleUniverse univ = new SimpleUniverse(canvas3D);
univ.getViewingPlatform().setNominalViewingTransform();
univ.addBranchGraph(scene);
}
public BranchGroup createSceneGraph() throws Exception
{
BranchGroup root = new BranchGroup();
// A white background.
Background bgd = new Background(1.0f, 1.0f, 1.0f);
root.addChild(bgd);
// This will spin the quad around
TransformGroup spin = new TransformGroup();
spin.setCapability(TransformGroup.ALLOW_TRANSFORM_WRITE);
root.addChild(spin);
// define the quad:
Point3d p1 = new Point3d(-0.5, -0.5, 0);
Point3d p2 = new Point3d(0.5, -0.5, 0);
Point3d p3 = new Point3d(0.5, 0.5, 0);
Point3d p4 = new Point3d(-0.5, 0.5, 0);
// colors
Color4b c = new Color4b((byte)255, (byte)0, (byte)0, (byte)255);
//Color3b c = new Color3b((byte)255, (byte)0, (byte)0);
QuadArray quads = new QuadArray(4,
GeometryArray.COORDINATES | GeometryArray.COLOR_4);
// GeometryArray.COORDINATES | GeometryArray.COLOR_3);
quads.setCoordinate(0, p1);
quads.setCoordinate(1, p2);
quads.setCoordinate(2, p3);
quads.setCoordinate(3, p4);
quads.setColor(0, c);
quads.setColor(1, c);
quads.setColor(2, c);
quads.setColor(3, c);
// Not sure if I need this. Doesn't seem to make a difference.
Appearance appearance = new Appearance();
TransparencyAttributes trans = new TransparencyAttributes();
trans.setTransparencyMode(TransparencyAttributes.BLENDED);
appearance.setTransparencyAttributes(trans);
// Create the shape...
Shape3D shape = new Shape3D();
shape.setGeometry(quads);
shape.setAppearance(appearance);
spin.addChild(shape);
Alpha rotationAlpha = new Alpha(-1, 4000);
RotationInterpolator rotator = new RotationInterpolator(rotationAlpha, spin);
BoundingSphere bounds = new BoundingSphere();
rotator.setSchedulingBounds(bounds);
spin.addChild(rotator);
return root;
}
public static void main(String[] args) throws Exception
{
Frame frame = new MainFrame(new Hello(), 256, 256);
}
}
解决方案
与Color4f更换Color4b,为我工作。在与下面的行的代码替换相应的线路,
Color color = new Color(255, 0, 0, 50);
Color4f c = new Color4f(color);
QuadArray quads = new QuadArray(4,
GeometryArray.COORDINATES | GeometryArray.COLOR_4);
我使用AWT颜色,发现它更容易在所有ColorNx()构造函数传递,即Color3b(),Color4b(),和Color4f()等,你可以直接使用float参数,如果感觉自然给你。实际的解决办法是使用Color4f的,而不是AWT啄。即使使用AWT颜色没有解决Color4b问题。只是Color4f去,我看不出有什么问题。
我的平台: Java版本 “1.6.0_10” Java 3D的1.5.2,酷睿双核,11.0 openSUSE当中,英特尔G33图形
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